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Tpy6a [65]
3 years ago
9

Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of

carbon dioxide and argon. The partial pressure of carbon dioxide is 0.080 atm and the partial pressure of argon is 0.24 atm
Chemistry
1 answer:
GarryVolchara [31]3 years ago
8 0

The given question is incomplete. The complete question is :

Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of carbon dioxide and argon. The partial pressure of carbon dioxide is 0.080 atm and the partial pressure of argon is 0.24 atm. What is the total pressure of the mixture.

Answer:  0.32 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{CO_2}+p_{Ar}

Given : p_{total} =total pressure of gases = ?

p_{CO_2} = partial pressure of carbon dioxide = 0.080 atm

p_{Ar} = partial pressure of argon = 0.24 atm    

putting in the values we get:

p_{total}=0.080atm+0.24atm  

p_{total}=0.32atm

Thus the total pressure of the gases is 0.32 atm

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The chemical force for which of the following ions is directed into the cell? The chemical force for which of the following ions
Over [174]

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5 0
3 years ago
What pressure is required to compress 196.0 liters of air at 1.83 atmosphere into a cylinder whose volume is 26.0 liters
drek231 [11]

Answer:

P₂ = 13.79 atm

Explanation:

Given data:

Initial volume = 196.0 L

Initial pressure = 1.83 atm

Final volume = 26.0 L

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

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5 0
3 years ago
When aqueous solutions of Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the mass of PbSO4 formed when 1.25 L of 0
neonofarm [45]

Answer:

The mass of PbSO4 formed 15.163 gram

Explanation:

mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625

mole of Na₂SO₄ = 2 x 0.025 = 0.05

                                      Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃

( Mole/Stoichiometry )    \frac{0.0625}{1}           \frac{0.05}{1}

                                     = 0.0625     = 0.05

From  (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.

Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄

                                            = 0.05 x 303.26 g

                                            = 15.163 g

7 0
3 years ago
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