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djyliett [7]
3 years ago
5

How many moles Of H2O will be produced from 42.0 g of H2O2?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
3 0
Molar{Mass} H_{2}O_{2} =2*16.0+2*1.0= 34.0 g/mol

42.0 g H_{2}O_{2}* \frac{1 mol H_{2}O_{2}}{34.0 g H_{2}O_{2}} = 1.24 mol H_{2}O_{2}

2H_{2}O_{2} --\ \textgreater \ 2 H_{2}O +O_{2}
\\2 mol  ----2 mol   (from// reaction)

\\1.24 mol ---1.24 mol (from  the problem)

Answer: 1.24 mol H_{2}O.
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Which is true about the pH values of a 1.0 M solution of HCl (a strong acid) and a 1.0 M solution of HC2H3O2 (a weak acid)?
Neko [114]

Answer:

C. pH values are different because the HC_2H_3O_2 solution partially ionizes and the HCl solution ionizes 100 percent.

Explanation:

Strong acids are the acids which completely ionizes in the solution while weak acids are the acids which ionizes partially in the solution. They exists in equilibrium in the solution with their respective ions.

Thus, strong acids furnish greater concentration of protons as compared to weak acid when same concentration of both types are taken.

<u>Also, pH is the negative of the logarithm  of the hydrogen ions. Thus, hydrogen ion concentration for both acids are different and thus pH will be different.</u>

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3 years ago
A certain amount of hydrogen peroxide was dissolved in 100. mL of water and then titrated with 1.68 M KMnO4. What mass of H2O2 w
Stels [109]

Answer:

see explanation below

Explanation:

First to all, this is a redox reaction, and the reaction taking place is the following:

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According to this reaction, we can see that the mole ratio between the peroxide and the permangante is 5:2. Therefore, if the titration required 21.3 mL to reach the equivalence point, then, the moles would be:

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But like it was stated before, the mole ratio is 5:2 so:

5MhVh = 2MpVp

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nh = 2MpVp/5

nh = 2 * 1.68 * 0.0213 / 5

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8 0
3 years ago
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natka813 [3]

Complete Question

The complete question is shown on the first uploaded image

Answer:

X  is Be

Y  is B

Z  is  O            

Explanation:

In order to understand the solution, we need to that the an element form a bond based on

1  The number of valence electron available in its atom

2 The  number of electron it require to attains its stable state i.e its Octet  state

        The number of valence electron for each of the option  are

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Now looking  option we can see that  Be has two valence  electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be

Considering the second  element              

      We see that  Y is donating  three valence electron in its atom and it is donating it to 3  Cl as Cl  only requires a single electron to achieve its stable state    

    Now looking  option we can see that  B has three valence  electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B

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      We see that  Z is donating two valence electron in its atom and it is donating it to 2  Cl as Cl  only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron

       Now looking at the option we can see that  O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron

   Therefore the correct option to this question is  O                  

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ELEN [110]
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