The major alkene product that results when n,n-dimethylhexan-2-amine undergoes cope elimination is hexene or hex-1-ene.
The reaction in which an amine is oxidize to an intermediate called an N-oxide which , when heated , acts as base in an intramolecular elimination reaction. The oxidation of tertiary amine into N-oxide is called cope reaction.
This elimination gives the less substituted alkene along with more substituted alkene which is Zaitsev product.
Example: Cope elimination of n,n-dimethylhexan-2-amine form hexene.
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Answer:
RBCs are disc-shaped with a flatter, concave center. This biconcave shape allows the cells to flow smoothly through the narrowest blood vessels. ... Many RBCs are wider than capillaries, but their shape provides the needed flexibility to squeeze through
Answer:
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1
Explanation:
because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
Answer:
They are similarly charged, which is why they repel each other.
First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
