Word-Definition
Pure substance- 4
Matter- 2
Atom- 1
Molecule- 3
Element- 5
Answer:
Option B. Decreasing the temperature of the solvent
Explanation:
Solubility is mostly enhanced by increasing the temperature of the solvent or solution. This means that am increase in temperature will increase the solubility and decreasing the temperature will decrease the solubility.
Answer: There are 6.9 mol of
are required to react completely with 2.30 mol of S.
Explanation:
The given reaction equation is as follows.
![S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)](https://tex.z-dn.net/?f=S%28s%29%20%2B%203F_%7B2%7D%28g%29%20%5Crightarrow%20SF_%7B6%7D%28g%29)
Here, 1 mole of S is reaction with 3 moles of
which means 1 mole of S requires 3 moles of
.
Therefore, moles of
required to react completely with 2.30 moles S are calculated as follows.
![1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}](https://tex.z-dn.net/?f=1%20mol%20S%20%3D%203%20mol%20F_%7B2%7D%5C%5C2.30%20mol%20S%20%3D%203%20mol%20F_%7B2%7D%20%5Ctimes%202.30%20%5C%5C%3D%206.9%20mol%20F_%7B2%7D)
Thus, we can conclude that there are 6.9 mol of
are required to react completely with 2.30 mol of S.
Answer:
Value of
for the given redox reaction is ![1.0\times 10^{-8}](https://tex.z-dn.net/?f=1.0%5Ctimes%2010%5E%7B-8%7D)
Explanation:
Redox reaction with states of species:
![14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)](https://tex.z-dn.net/?f=14H%5E%7B%2B%7D%28aq.%29%2BCr_%7B2%7DO_%7B7%7D%5E%7B2-%7D%28aq.%29%2B6Cl%5E%7B-%7D%28aq.%29%5Crightarrow%202Cr%5E%7B3%2B%7D%28aq.%29%2B3Cl_%7B2%7D%28g%29%2B7H_%7B2%7DO%28l%29)
Reaction quotient for this redox reaction:
![Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}](https://tex.z-dn.net/?f=Q_%7Bp%7D%3D%5Cfrac%7B%5BCr%5E%7B3%2B%7D%5D%5E%7B2%7D.P_%7BCl_%7B2%7D%7D%5E%7B3%7D%7D%7B%5BH%5E%7B%2B%7D%5D%5E%7B14%7D.%5BCr_%7B2%7DO_%7B7%7D%5E%7B2-%7D%5D.%5BCl%5E%7B-%7D%5D%5E%7B6%7D%7D)
Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of
is taken as 1 due to the fact that
is a pure liquid.
![pH=-log[H^{+}]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%7B%2B%7D%5D)
So, ![[H^{+}]=10^{-pH}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D10%5E%7B-pH%7D)
Plug in all the given values in the equation of
:
![Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}](https://tex.z-dn.net/?f=Q_%7Bp%7D%3D%5Cfrac%7B%280.10%29%5E%7B2%7D%5Ctimes%20%280.010%29%5E%7B3%7D%7D%7B%2810%5E%7B-0.0%7D%29%5E%7B14%7D%5Ctimes%20%281.0%29%5Ctimes%20%281.0%29%5E%7B6%7D%7D%3D1.0%5Ctimes%2010%5E%7B-8%7D)
Answer:
Rn
Explanation:
Rn is the symbol for radon with the atomic number of 86