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pochemuha
3 years ago
14

The mode of 1.5, 1.6, 2, 2, 3.4, 5.6, 5.9 is 3.14. True False

Mathematics
1 answer:
inessss [21]3 years ago
6 0
The answer is FALSE, the mode in a sequence is the number that appears most often; the mode is 2.
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If two events are mutually​ exclusive, why is ​? Choose the correct answer below. A. because A and B each have the same probabil
svetlana [45]

Answer:

B. because A and B cannot occur at the same time.

Step-by-step explanation:

If two events are mutually​ exclusive, why is ​? Choose the correct answer below.

A. because A and B each have the same probability.

B. because A and B cannot occur at the same time.

C. because A and B are independent.

D. because A and B are complements of each other.

3 0
3 years ago
Need help please !!!!!<br><br> Will mark as brainliest!!!!<br><br> (Don’t mind my answers)
Alika [10]

Answer:

Can you give me the choices for each of these, I'm not sure how they might phrase it.

3 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min, and its coarseness is such that it forms a pile in the shap
pogonyaev

Answer:

Rate of increase in height =\frac{dh}{dt}=0.3156ft/min

Step-by-step explanation:

we know that volume of a cone is given by

V=\frac{1}{12}\pi d^{2}h

It is Given that diameter equals height thus we have

V=\frac{1}{12}\pi h^{2}h\\\\V=\frac{1}{12}\pi h^{3}

Differentiating both sides with respect to time we get

\frac{dV}{dt}=\frac{1}{12}\pi \frac{dh^{3}}{dt}\\\\\frac{dV}{dt}=\frac{1}{12}\pi(3h^{2}\frac{dh}{dt})

Applying values and solving for \frac{dh}{dt} we get

\frac{dh}{dt}=\frac{12\frac{dV}{dt}}{3\pi h^{2}}\\\\\frac{dh}{dt}=0.3156ft/min

8 0
3 years ago
(1 point) A pond contains 100 fish, of which 40 are carp. If 20 fish are caught from the lake, what are the mean and variance of
marta [7]

Answer:

E(X) = 6

Var(X) = 3.394

Step-by-step explanation:

Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each

of the (100, 20) ways to catch the 20 fishes will be equally likely.

Thus, we can say that X fulfills a hypergeometric

distribution with parameters as follows;

n = 20, N = 100, k = 30

Formula for expected mean value in hypergeometric distribution is;

E(X) = nk/N

E(X) = (20 × 30)/100

E(X) = 6

Formula for variance is;

Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]

Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]

Var(X) = 6 × 0.5657

Var(X) = 3.394

5 0
2 years ago
Which statements describe the functions? Check all
ruslelena [56]

Answer:

a,d,e

Step-by-step explanation:

edgenuity

6 0
3 years ago
Read 2 more answers
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