All categories

4 years ago

Please help idk this

Mathematics

1 answer:

Shalnov [3]4 years ago

8 0

Answer:

DF is congruent to ZX

Step-by-step explanation:

Pls make branliest.

You might be interested in

Find the equation of a line that passes through the given points<br>(-6,-5) and (6,-13)

NeTakaya

Answer:

y+5=-3/4(x+6)

or in slope intercept

y= -3/4x-38/4

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5--13}{-6-6}=\frac{-5+13}{-6+-6}=\frac{8}{-12}=\frac{-3}{4}$

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--5)=-3/4(x--6)

y+5=-3/4(x+6)

y+5=-3/4x-18/4

y=-3/4x-18/4-20/4

y= -3/4x-38/4

5 0

4 years ago

Read 2 more answers

An item is regularly priced at $40 It is on sale for 30% off the regular price. How much (in dollars) is discounted from the reg

Ipatiy [6.2K]

12 dollars is discounted off, making the price 28 dollars.

Step-by-step explanation:

10 percent is 4$, 4×3=12

5 0

2 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$