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Leviafan [203]
2 years ago
11

Need help As soon as possible!!

Mathematics
1 answer:
emmasim [6.3K]2 years ago
4 0
I think the fourth option is the answer. It wi give you the Side angle side postulate.
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I'd love some help on this question. I do not understand how you would go about working this out, so please explain the working
zhannawk [14.2K]
Area = length x width and volume = length x width x height soo you would have to multiple 4 and 25 and that’s 100
7 0
2 years ago
Please help me......................
maksim [4K]

Answer:

Mr brickman

Step-by-step explanation:

the frequency

6 0
2 years ago
Insert three arithmetic means between 4 and 10.
Bumek [7]

Answer:

5.5, 7, 8.5

Step-by-step explanation:

Find the mean of 4 and 10, that is

\frac{4+10}{2} = \frac{14}{2} = 7

Now repeat with 4 and 7 and 7 and 10

\frac{4+7}{2} = \frac{11}{2} = 5.5

\frac{7+10}{2} = \frac{17}{2} = 8.5

Hence

4, 5.5, 7, 8.5, 10 ← is an arithmetic sequence with d = 1.5

4 0
3 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
2 years ago
Ty bought 5 folders that cost $3 each. How much did he spend on folders?
Novay_Z [31]
5 x 3 = 15

Ty spent $15 on binders
3 0
3 years ago
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