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Leviafan [203]
3 years ago
11

Need help As soon as possible!!

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0
I think the fourth option is the answer. It wi give you the Side angle side postulate.
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Find the vertex of the quadratic function
Galina-37 [17]

Answer:

(1.5,2.5)

Step-by-step explanation:

f(x) = 2x^2 - 6x + 7

Take the first derivative and set it equal to 0 (the slope is 0 at the vertex)

f'(x) = 4x -6

0 = 4x - 6

4x = 6

x = 3/2 or 1.5

If x = (3/2), then y = 2(3/2)^2 - 6(3/2) + 7

y = 2(9/4) - 18/2 + 7

y = (9/2) - 2

y = 2.5

See attached graph.

8 0
2 years ago
Can someone do these two questions for me please. I have a lot of homework to do and I'm trying to get a lot of questions done a
olga_2 [115]

Answer:

1. is 25

2. I think this one is 25 too?

Step-by-step explanation:

im working on the second

6 0
3 years ago
Read 2 more answers
Solve for x: tan(180-ø).tan(90+ø)+xcos(90+ø).(cos90-ø) =sinø.(sin180-ø) ​
Burka [1]
Is there a picture that I’m able to look at??
5 0
3 years ago
Read 2 more answers
Line segment ST is dilated to create line segment S'T' using the dilation rule DQ,2. 25. Point Q is the center of dilation. Line
abruzzese [7]

The distance between points S' and S is x= 2.5 units.

<h2>Given that</h2>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ 2. 25.

Point Q is the center of dilation.

Line segment ST is dilated to create line segment S prime T prime.

The length of QT is 1. 2 and the length of QS is 2.

The length of SS prime is x and the length of TT prime is 1. 5.

<h3>We have to determine</h3>

What is x, the distance between points S' and S?

<h3>According to the question</h3>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ, 2.25.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5, SS' = x.

Since the line ST is dilated to S'T' with the center of dilation Q, the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q.

\dfrac{SQ}{S'Q} = \dfrac{TQ}{T'Q}\\&#10;\\&#10;\dfrac{SQ}{SQ+SS} = \dfrac{TQ}{TQ+TT'}\\&#10;\\ &#10;\dfrac{2}{2+x} = \dfrac{1.2}{1.2+1.5}\\\rm &#10;\\&#10;\dfrac{2}{2+x} = \dfrac{1.2}{2.7}\\\\ \dfrac{2}{2+x} = \dfrac{12}{27}\\\\2(27) = (2+x) 12\\\\ 54 = 24 + 12x\\&#10;\\&#10;12x = 54-24\\&#10;\\&#10;12x=30\\&#10;\\&#10;x = \dfrac{30}{12}\\&#10;\\&#10;x = 2.5

Hence, the distance between points S' and S is x= 2.5 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/16016926

5 0
2 years ago
Show how to get answer 2 for $24.99 or 5 for $58.99
bija089 [108]
You normally use division what u do is u did if 24.99 by 2
24.99 \div 2 = 12.495
8 0
3 years ago
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