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kari74 [83]
2 years ago
7

The solubility of a solute (a dissolved substance) in a solvent (the dissolving medium) is the most important chemical principle

.
a. True
b. False
Chemistry
1 answer:
Leya [2.2K]2 years ago
6 0

Answer:

False

Explanation:

The most important chemical principle is not just one, there are several, such as the constitution of an atamo among others.

The important thing about this principle is that solutes can be dissolved in solvents where as a product they give a solution.

According to the amount of solute, three types of solutions can be observed:

Supersaturated solutions, where the solute is in excess and part cannot be integrated into the solvent, precipitating in the lower part of the container.

Saturated solutions, where the solute is in the right concentration so that it does not precipitate and constantly interacts in a cyclical way with the solvent.

Subsaturated solutions, where the amount of the solute is small.

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Which of the following is NOT a fate for pyruvate?
son4ous [18]

Answer: The conversion to malate  

Explanation:

Pyruvate is the process which produced in glycoysis which has multiple fates and it can give rises to acetyl co-enzyme and undergo the aerobic oxidation in the critic acid cycle. It can be used to produces glucose but it never produced the malate. In prokaryotes it can be processes in the anaerobic respiration to produced the ethanol, as end product.

6 0
2 years ago
calculate the mass of calcium phosphate and the mass of sodium chloride that could be formed when a solution containing 12.00g o
Leviafan [203]

Answer : The mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

Explanation : Given,

Mass of Na_3PO_4 = 12.00 g

Mass of CaCl_2 = 10.0 g

Molar mass of Na_3PO_4 = 164 g/mol

Molar mass of CaCl_2 = 111 g/mol

Molar mass of NaCl = 58.5 g/mol

Molar mass of Ca_3(PO_4)_2 = 310 g/mol

First we have to calculate the moles of Na_3PO_4 and CaCl_2.

\text{Moles of }Na_3PO_4=\frac{\text{Given mass }Na_3PO_4}{\text{Molar mass }Na_3PO_4}

\text{Moles of }Na_3PO_4=\frac{12.00g}{164g/mol}=0.0732mol

and,

\text{Moles of }CaCl_2=\frac{\text{Given mass }CaCl_2}{\text{Molar mass }CaCl_2}

\text{Moles of }CaCl_2=\frac{10.0g}{111g/mol}=0.0901mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is:

2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2

From the balanced reaction we conclude that

As, 3 mole of CaCl_2 react with 2 mole of Na_3PO_4

So, 0.0901 moles of CaCl_2 react with \frac{2}{3}\times 0.0901=0.0601 moles of Na_3PO_4

From this we conclude that, Na_3PO_4 is an excess reagent because the given moles are greater than the required moles and CaCl_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NaCl  and Ca_3(PO_4)_2

From the reaction, we conclude that

As, 3 mole of CaCl_2 react to give 6 mole of NaCl

So, 0.0901 mole of CaCl_2 react to give \frac{6}{3}\times 0.0901=0.1802 mole of NaCl

and,

As, 3 mole of CaCl_2 react to give 1 mole of Ca_3(PO_4)_2

So, 0.0901 mole of CaCl_2 react to give \frac{1}{3}\times 0.0901=0.030 mole of Ca_3(PO_4)_2

Now we have to calculate the mass of NaCl  and Ca_3(PO_4)_2

\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl

\text{ Mass of }NaCl=(0.1802moles)\times (58.5g/mole)=10.5g

and,

\text{ Mass of }Ca_3(PO_4)_2=\text{ Moles of }Ca_3(PO_4)_2\times \text{ Molar mass of }Ca_3(PO_4)_2

\text{ Mass of }Ca_3(PO_4)_2=(0.030moles)\times (310g/mole)=9.3g

Therefore, the mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

5 0
2 years ago
Which of the following statements best describes a difference between mechanical waves and electromagnetic waves?
kipiarov [429]
The correct answer is the 3rd one  
6 0
3 years ago
gold(iii) chloride reacts with Antimony(III) oxide and water to produce Gold Antimony(V) oxide and Hydrochloric acid balanced eq
zhuklara [117]
Balanced equation below

5 0
3 years ago
Difference between element and radical​
Romashka-Z-Leto [24]

Answer:

A radical is a group of atoms behaving as a unit in a number of compounds where as an element is a species of atoms having the same number of protons in their atomic nuclei.

Explanation:

6 0
2 years ago
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