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eimsori [14]
3 years ago
13

Arrange the compounds in order of decreasing magnitude of lattice energy:

Chemistry
1 answer:
Alik [6]3 years ago
8 0

Answer:

The correct answer is CaO > LiBr > KI.

Explanation:

Lattice energy is directly proportional to the charge and is inversely proportional to the size. The compound LiBr comprises Li+ and Br- ions, KI comprises K+ and I- ions, and CaO comprise Ca²⁺ and O²⁻ ions.  

With the increase in the charge, there will be an increase in lattice energy. In the given case, the lattice energy of CaO will be the highest due to the presence of +2 and -2 ions. K⁺ ions are larger than Li⁺ ion, and I⁻ ions are larger than Br⁻ ion.  

The distance between Li⁺ and Br⁻ ions in LiBr is less in comparison to the distance between K⁺ and I⁻ ions in KI. As a consequence, the lattice energy of LiBr is greater than KI. Therefore, CaO exhibits the largest lattice energy, while KI the smallest.  

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Vinil7 [7]
Boiling I think! hope you get it right
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3 years ago
Nitrogen monoxide and oxygen, both colorless gases, form a red-brown gas when mixed. Nitrogen monoxide and oxygen are called the
daser333 [38]

Answer:

Nitrogen monoxide and oxygen are called the reactants

Explanation:

Step 1: Given data

Nitrogen monoxide = NO

Oxygen = O2

Step 2: Balanced equation

2NO + O2 → 2NO2

This means that 2 moles of NO will be consumed and and 1 mole of O2 to produce 2 moles of NO2

This means NO2 is the prodcut that is produced.

NO +O2 react with eachother, to form NO2

This means nitrogen monoxide (NO) and Oxygen (O2) are called the reactants.

5 0
3 years ago
The unheated Gas in the above system has a volume of 20.0 L at a temperature of 25.0 C and a pressure of 1.00 atm. The gas is he
kipiarov [429]

Answer:

1.25 atm.

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 20L

Initial temperature (T1) = 25°C

Initial pressure = 1 atm

Final temperature (T2) = 100°C

Final volume (V2) = constant i.e remain the same

Final pressure (P2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below:

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 25°C = 25°C + 273 = 298K

Final temperature (T2) = 100°C = 100°C + 273 = 373K

Step 3:

Determination of the final pressure of the gas. This is illustrated below:

Since the volume is constant, the following equation, P1/T1 = P2/T2 will be used to obtain the final pressure of gas as follow:

P1/T1 = P2/T2

Initial temperature (T1) = 298k

Initial pressure = 1 atm

Final temperature (T2) = 373K

Final pressure (P2) =?

P1/T1 = P2/T2

1/298 = P2 /373

Cross multiply to express in linear form

298 x P2 = 1 x 373

Divide both side by 298

P2 = 373/298

P2 = 1.25 atm.

Therefore, the pressure of the heated gas is 1.25 atm.

3 0
3 years ago
flammable liquid is being pumped out of a drum into a bucket using a hand pump. describe an appropriate grounding and bonding pr
lutik1710 [3]

When transferring flammable liquids from storage drums to smaller electrically conductive containers, bonding and grounding are required. In any workplace, you should do the same whenever you move these liquids between conductive containers.

<h3>What exactly occurs in this case?</h3>

Ground dispensing drums in the area for storing and dispensing flammable liquids. Connecting the container to an already grounded, electrically conductive object grounds it. This could be a grounded metal construction framework, a buried metal plate, a metallic subsurface gas piping system, or metal water pipes. Sparks are prevented from discharging by bonding the two containers together and grounding one of them. All connections for bonding and grounding must be made from bare metal to bare metal.

To know more about Flammable liquids, visit-brainly.com/question/3702349

#SPJ4

3 0
1 year ago
Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution.
Zina [86]

Answer:

V = 1.66mL acetic acid

Explanation:

dilution formula:

V1*C1 =V2*C2

⇒ V1*(6M) = (100mL)*(0.1M)

⇒ V1 =( (100mL) * (0.1M) ) / (6M)

⇒ V1 = 1.66mL acetic acid

8 0
3 years ago
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