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3 years ago

If velocity is 0.2m/s, what is the kinetic energy?

Physics

1 answer:

Natalija [7]3 years ago

3 0

$\huge\boxed{♧ \: \mathfrak{ \underline{Answer} \: ♧}}$

we know,

$\boxed{kinetic \: \: energy = \frac{1}{2} m {v}^{2} }$

So,

$\longmapsto \dfrac{1}{2} \times 10 \times 0.2 \times 0.2$

$\longmapsto0.2 \: joules$

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Answer:

Explanation:

given,

initial velocity of the ball = 20 m/s

angle of ramp = 22°

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$v^2 = u^2 - 2gh$

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$v = \sqrt{20^2- 2\times 9.8 \times 5 cos 22^0 }$

v = 17.58 m/s

b) considering the friction

$\dfrac{1}{2}mv^2 = \dfrac{1}{2}mu^2 - mgh-\mu_kmgl$

$v^2 = u^2 - 2gh-2\mu_kmgl$

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3 years ago

If a battery is running down, a light bulb in the circuit will become dimmer because when voltage drops

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2 years ago

What energy transformations take place when you eat a taco and then go for a jog

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Answer:

Chemical to kinetic and thermal.

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3 years ago

A ball has a mass of 2g and a velocity of 3m/s. What is the ball's Kinetic Energy?

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3 years ago

Suppose an automobile has 2000-joules of kinetic energy. when it moves at twice the speed, what will be its kinetic energy? what

NeX [460]

Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

$K.E = \frac{1}{2}mv^2\\$ ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

$K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\$

using equation (1):

For thrice speed:

vₓ = 3v

then,

$K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\$

using equation (1):

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3 years ago