3 years ago

If velocity is 0.2m/s, what is the kinetic energy?

Physics

1 answer:

Natalija [7]3 years ago

3 0

$\huge\boxed{♧ \: \mathfrak{ \underline{Answer} \: ♧}}$

we know,

$\boxed{kinetic \: \: energy = \frac{1}{2} m {v}^{2} }$

So,

$\longmapsto \dfrac{1}{2} \times 10 \times 0.2 \times 0.2$

$\longmapsto0.2 \: joules$

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A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Phoenix [80]

Answer:

The particle path will follow

(d) a circular path

Explanation:

When a charged particle having charge of magnitude ' $q$ ' enters into a magnetic field such that its velocity vector ' $\vec{V}$ ' is perpendicular to the direction of the magnetic field ' $\vec{B}$ ', then it will experience a force, called Lorentz force ( $\vec{F_{L}}$ ), given by

$\vec{F_{L}} = \vec{V} \times \vec{B}$

As shown in the figure, the magnetic field is directed perpendicular to the plane and towards the plane (as shown by the circle and 'X'-sign) and the velocity vector is from left to right on the plane.

According to the property of cross-product, the Lorentz force ( $F_{L}$ ) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path,as shown in the figure.