The nuclear fusion of hydrogen atoms releases a huge amount of energy. So the correct choice is C. Conversion of mass to energy.
What is nuclear fusion?
When two small nuclei join to form a new nucleus, then this process is termed nuclear fusion. A huge amount of energy is released when there occurs nuclear fusion between the two nuclei. And a new element is formed.
It has been observed that the amount of energy released in nuclear fusion is equal to the mass difference between the mass of the formed nucleus and the total mass of old nuclei. Hence in the nuclear fusion of hydrogen nuclei to form a helium nucleus, the energy is released due to the conversion of mass into energy.
The pressure is increased to make the hydrogen atoms fuse but this change in pressure does not contribute to the energy released in the fusion of hydrogen.
The magnitude of the gravitational field is too low and it does not contribute to the energy released in the fusion of hydrogen.
The gravitational collapse does not occur between the two hydrogen atoms. This phenomenon occurs in celestial bodies so this also does not contribute to the energy released in the fusion of hydrogen.
Learn more about nuclear fusion here:
brainly.com/question/10165218
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Answer:
The answer to your question is 1.35 Watts
Explanation:
Data
Work = W = 5 J
time = t = 3.7 s
Power = P = ?
Formula
Power is a rate in which work is done or energy is transferred over time
P = ![\frac{W}{t}](https://tex.z-dn.net/?f=%5Cfrac%7BW%7D%7Bt%7D)
Substitution
![P = \frac{5}{3.7}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B5%7D%7B3.7%7D)
Result
P = 1.35 W
Answer:
W = 2352 J
Explanation:
Given that:
- mass of the bucket, M = 10 kg
- velocity of pulling the bucket, v = 3
![m.min^{-1}](https://tex.z-dn.net/?f=m.min%5E%7B-1%7D)
- height of the platform, h = 30 m
- rate of loss of water-mass, m =
![0.4 kg.min^{-1}](https://tex.z-dn.net/?f=0.4%20kg.min%5E%7B-1%7D)
Here, according to the given situation the bucket moves at the rate,
![v=3 m.min^{-1}](https://tex.z-dn.net/?f=v%3D3%20m.min%5E%7B-1%7D)
The mass varies with the time as,
![M=(10-0.4t) kg](https://tex.z-dn.net/?f=M%3D%2810-0.4t%29%20kg)
Consider the time interval between t and t + ∆t. During this time the bucket moves a distance
∆x = 3∆t meters
So, during this interval change in work done,
∆W = m.g∆x
<u>For work calculation:</u>
![W=\int_{0}^{10} [(10-0.4t).g\times 3] dt](https://tex.z-dn.net/?f=W%3D%5Cint_%7B0%7D%5E%7B10%7D%20%5B%2810-0.4t%29.g%5Ctimes%203%5D%20dt)
![W= 3\times 9.8\times [10t-\frac{0.4t^{2}}{2}]^{10}_{0}](https://tex.z-dn.net/?f=W%3D%203%5Ctimes%209.8%5Ctimes%20%5B10t-%5Cfrac%7B0.4t%5E%7B2%7D%7D%7B2%7D%5D%5E%7B10%7D_%7B0%7D)
![W= 2352 J](https://tex.z-dn.net/?f=W%3D%202352%20J)