It’s A dalton he is the one who figured out matter
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
como se denomina el proceso utilizado para descomponer el agua
Answer:
4.567 ltr
Explanation:
both are gases
so
N2 +Br2 =NBr3
balancing
N2 +3B2 = 2 NBr3
now
3 litr of B2 gives 2 liter of NBr3
6.85 litr of B2 gives 2/3 *6.85 litr NBr3 = 4.567ltr
Molar mass HCl = 36.5 g/mol
number of moles:
mass of solute / molar mass:
9.63 / 36.5 => 0.263 moles
Volume = 1.5 L
M = n / V
M = 0.263 / 1.5
M = 0.1753 mol/L
espero ter ajudado!
