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LenaWriter [7]
3 years ago
9

What is rounding off nearest hundred​

Mathematics
2 answers:
Lelu [443]3 years ago
4 0

Answer:

well, rounding to the nearest hundred is to the nearest hundred. For example, 151 rounded to the nearest hundred is 200, and 149 is 100.

Step-by-step explanation:

blsea [12.9K]3 years ago
3 0

Answer:

Step-by-step explanation:

Rounding off to the nearest hundred is rounding to the nearest hundred

Ex: round 515315 to the nearest hundred

515,315 = 515,300

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On Monday, three hundred ninety - two students went on a trip to the zoo. All nine buses were filled and five students had to tr
Vikki [24]
The answer to your question is 43
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Given the function g(x)=−2x−8, evaluate g(0).
Vera_Pavlovna [14]

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g(0) = -8

Step-by-step explanation:

When you plug in a zero for the x the equation will look like

g(0) = -2(0) - 8

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As an estimation we are told 5 miles is 8 km.
melamori03 [73]

Answer:

Step-by-step explanation:

52.5 mi(8 km/5mi) = 84 km

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3 years ago
Your friend is trying to grow her hair as long as her cousin's hair. The table (attached) shows their hair lengths (in inches) i
astra-53 [7]

Answer:

a)  y = 1/2x + 5/2

    y = 2/5x + 29/5

b)  hair will be 19 inches for both at 33 months

Step-by-step explanation:

a) rate of growth of friend's hair:  (3, 4) (8, 6.5)  

(6.5 - 4) ÷ (8 - 3) = 2.5/5 or 1/2

find the y-intercept of equation for growth of friend's hair:

y = mx + b

4 = 1/2(3) + b

4 = 3/2 + b

8/2 - 3/2 = b

5/2 = b

equation for growth of friend's hair:

y = 1/2x + 5/2

rate of growth of cousin's hair:  (3, 7) (8, 9)  

(9 - 7) ÷ (8 - 3) = 2/5

find the y-intercept of equation for growth of cousin's hair:

y = mx + b

9 = 2/5(8) + b

9 = 16/5 + b

45/5 - 16/5 = b

29/5 = b

equation for growth of cousin's hair:

y = 2/5x + 29/5

b) y = 1/2x + 5/2

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5/10x + 25/10 = 4/10x + 58/10

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x = 33

8 0
2 years ago
How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?
arlik [135]

Answer:

5 Outer and 1 lone pair

Step-by-step explanation:

A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.

Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is sp^{3} d^2.

One of the most common example is Xenon tetraflouride. XeF_4. Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.

4 0
3 years ago
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