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Gekata [30.6K]
3 years ago
11

How much is 5+5+8+7+9+5+9+5+3=

Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

56

Step-by-step explanation:

56................

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X=a+b+4 and a~y^2,b~1/y. when y=2, x=18 and when y=1, x=-3. find x when y=4​
Ugo [173]

Answer:

really hard

Step-by-step explanation:

ask sheldon

6 0
3 years ago
What was the speed during first and also cooldown
devlian [24]

Hi Braniac


S = his speed for the 1st 20 mi

(s-2) = His speed for the last 16 mi

We know that :

time= distance/ speed


initial time = cool down time

20/s = 16/(s-2)

Now cross multiply

20(s-2) =16s

20s-40=16s

20s-16s=40

4s = 40

Now we need to divide both sides by 4 so we can find the speed

4s/4 = 40/4

s= 10 mph

His initial speed is 10mph

Now let's find his cool down speed

10-2 = 8mph

His cool down speed is 8mph


I hope that's help :)


If you have any questions please let me know :)

7 0
3 years ago
Find three consecutive integers such that the sum of the first and third is 72
Minchanka [31]
23, 24, 25

23+24+27 equals 72
3 0
3 years ago
Read 2 more answers
Adam has 18 counters He gives 10 of the counters to Lesley
kumpel [21]

Answer:

Lesley has 10/18 counters

10/18= 5/9

So: Lesley has 5/9 of the 18 counters

7 0
1 year ago
The diagonals of rhombus ABCD intersect at E. Given that m∠CAD=20° and CE=4, find the m∠CDA.
V125BC [204]

Answer:

<em>< CDA = 140 degrees </em>

Step-by-step explanation:

For a rhombus, the sum of the interior angles is 360 degrees and also the opposite angles are equal i.e <ABC = <CDA and <BAD = <BCD

Given

<CAD = 20 degrees

<BCE = 20 degrees (based on geometry)

<BAD = <CAD + <BCE

<BAD = 20 + 20

<BAD = 40 degrees

Since  <BAD =  <BCD, then  <BCD = 40 degrees

Get <CDA

<CDA + <ABC + <BAD +   <BCD  = 360

<CDA + <CDA + <BAD +   <BCD  = 360

2 < CDA + 40 + 40 = 360

2< CDA + 80 = 360

2< CDA = 360-80

2< CDA = 280

< CDA = 280/2

<em>< CDA = 140 degrees </em>

6 0
3 years ago
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