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Vera_Pavlovna [14]
3 years ago
14

Please help this is important

Mathematics
2 answers:
MrRissso [65]3 years ago
5 0

Answer:

the answer is A=8.96 X 10 with a power of 7

aliya0001 [1]3 years ago
3 0
The answer is A , and photomath will help you with that easily
You might be interested in
Please help......
rosijanka [135]
1. using 2 dots that are on the blue line (0,72) and (6,69)
find the slope:

slope = change in Y over change in x = 69 - 72 / 6-0 = -3 / 6 = -1/2
 equation would be y = -1/2x + 72

2. y = -1/2x+72 = -1/2(30) +72 = -15 +72 = 57 beats per minute

3. replaced x in the equation with 30 to find the beats per minute for exercising 30 minutes

5 0
3 years ago
Destiny designs necklaces she used between 15 and 20 yellow and blue beads in a ratio of 4 yellow beads to 5 blue beads drag the
julia-pushkina [17]
Hey! :)

Well, the ratio of yellow beads to blue beads is 4:5. The best way I think is to guess and check multiplying the ratio by integers. You need between 15 and 20.4 : 5 ( = 9 too little )8 : 10 ( = 18 just right)12 : 15 ( = 27 too much)So per necklace, 8 yellow beads and 10 blue beads would be needed.

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
PLEASE HELP<br><br> simplify the expression<br><br> 2. 10r^(-7)t^3
Alina [70]
<span>10r^(-7)t^3
= 10t^3 / r^7

hope it helps</span>
4 0
3 years ago
What is the width of the rectangle shown below? <br>4x + 3 <br>A = 8x2 – 10x – 12
ozzi

Answer:

<h2><em>2x-4</em></h2>

Step-by-step explanation:

Area of a rectangle = Length * Width

Given parameters

Area A = 8x2 – 10x – 12

Length of the rectangle = 4x+3

Required

Width of the rectangle.

Substituting the given parameters into the formula

8x2 – 10x – 12  = (4x+3)*width

width = 8x2 – 10x – 12 /4x+3

S

Factorizing the numerator

8x² – 10x – 12

= 2(4x²-5x-6)

= 2(4x²-8x+3x-6)

= 2(4x(x-2)+3(x-2))

= 2(4x+3)(x-2)

Width = 2(4x+3)(x-2)/4x+3

Width = 2(x-2)

Width = 2x-4

<em>Hence the width of the rectangle is 2x-4</em>

8 0
3 years ago
Include parentheses in your answer.<br> (x3 + y3) ÷ (x - y)
-Dominant- [34]
I'm assuming you mean \frac{x^3+y^3}{x-y}

we can factor that sum of perfect cubes from x^2+y^3 into (x+y)(x^2-xy+y^2)

so therefor \frac{x^3+y^3}{x-y}=\frac{(x+y)(x^2-xy+y^2)}{x-y}
that is simpliest form

8 0
3 years ago
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