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Nataly [62]
3 years ago
14

A gas has a pressure of 1.00 atm and a volume of 500 mL. When its pressure is doubled, at constant temperature, to 2.00 atm, its

volume halves to 250 mL, following Boyle's Law. However, when its pressure is increased 1000 times, at constant temperature, to 1000 atm, the volume decreases to 2 mL which is more than 1/1000 of 500 mL. What is the reason why Boyle's Law is not obeyed when the pressure is increased to 1000 atm?
Chemistry
1 answer:
Advocard [28]3 years ago
3 0

Answer: The reason why Boyle's is not obeyed is because the size of the gaseous molecules is more appreciable compared to the volume of the container containing the gas.

Explanation: At such high pressure of 1000atm , there will be high amount of gaseous molecules in terms of numbers and the volume of the gas will not be able to be decreased as if the gaseous molecules were dimensionless. The piston of the container containing the gas will not be able to pushed down much because the molecules will require an appreciable space.

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675 g of carbon tetrabromide is equivalent to how many
VARVARA [1.3K]
<h3>Answer:</h3>

2.04 mol CBr₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

675 g CBr₄

<u>Step 2: Identify Conversions</u>

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Molar Mass of Br - 79.90 g/mol

Molar Mass of CBr₄ - 12.01 + 4(79.90) = 331.61 g/mol

<u>Step 3: Convert</u>

<u />\displaystyle 675 \ g \ CBr_4(\frac{1 \ mol \ CBr_4}{331.61 \ g \ CBr_4}) = 2.03552 \ mol \ CBr_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.03552 mol CBr₄ ≈ 2.04 mol CBr₄

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P = 1.2/100 * 62000 g = 7.44 * 10^2 g


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