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Nataly [62]
3 years ago
14

A gas has a pressure of 1.00 atm and a volume of 500 mL. When its pressure is doubled, at constant temperature, to 2.00 atm, its

volume halves to 250 mL, following Boyle's Law. However, when its pressure is increased 1000 times, at constant temperature, to 1000 atm, the volume decreases to 2 mL which is more than 1/1000 of 500 mL. What is the reason why Boyle's Law is not obeyed when the pressure is increased to 1000 atm?
Chemistry
1 answer:
Advocard [28]3 years ago
3 0

Answer: The reason why Boyle's is not obeyed is because the size of the gaseous molecules is more appreciable compared to the volume of the container containing the gas.

Explanation: At such high pressure of 1000atm , there will be high amount of gaseous molecules in terms of numbers and the volume of the gas will not be able to be decreased as if the gaseous molecules were dimensionless. The piston of the container containing the gas will not be able to pushed down much because the molecules will require an appreciable space.

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There is an error in the rate-determining step of the following proposed mechanism.
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Answer:

The steps with correct mechanism are given below:

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How many grams of Pb are contained in a mixture of 0.135 kg each of PbCl(OH) and Pb2Cl2CO3?
Dahasolnce [82]

Hey there!:

Given the mass of PbCl(OH) :

0.135 Kg = 0.135 Kg*(1000g / 1Kg)  = 135 g

Molecular mass of PbCl(OH)  = 207+35.5+16+1  = 259.5 g / mol

Atomic mass of Pb = 207 g/mol

Hence mass of Pb in 135 g  PbCl(OH)  :

(207 g Pb /  259.5 g PbClOH) * 135g PbClOH  =

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For Pb2Cl2CO3  :

Given the mass of Pb2Cl2CO3  :

0.135 Kg = 0.135 Kgx(1000g / 1Kg)  = 135 g

Molecular mass of Pb2Cl2CO3  = 2*207+2*35.5+12+3*16  = 545 g / mol

Mass of Pb present in 1 mol (=545 g / mol) of Pb2Cl2CO3  = 2*207 = 414 g

Hence mass of Pb in 135 g  Pb2Cl2CO3:

(414 g Pb /  545 g PbClOH) * 135g PbClOH  =

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