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Nataly [62]
2 years ago
14

A gas has a pressure of 1.00 atm and a volume of 500 mL. When its pressure is doubled, at constant temperature, to 2.00 atm, its

volume halves to 250 mL, following Boyle's Law. However, when its pressure is increased 1000 times, at constant temperature, to 1000 atm, the volume decreases to 2 mL which is more than 1/1000 of 500 mL. What is the reason why Boyle's Law is not obeyed when the pressure is increased to 1000 atm?
Chemistry
1 answer:
Advocard [28]2 years ago
3 0

Answer: The reason why Boyle's is not obeyed is because the size of the gaseous molecules is more appreciable compared to the volume of the container containing the gas.

Explanation: At such high pressure of 1000atm , there will be high amount of gaseous molecules in terms of numbers and the volume of the gas will not be able to be decreased as if the gaseous molecules were dimensionless. The piston of the container containing the gas will not be able to pushed down much because the molecules will require an appreciable space.

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consider an atom having four distinct neergy levels. if an electron is able to make transitions between, any two levels, how man
ludmilkaskok [199]

Answer:

6 different frequencies

Explanation:

From energy level 1 to 2 is one frequency, from energy level 1 to 3 is one frequency and From energy level 1 to 4 is one frequency. So, we have a total of 3 frequencies for transition from energy level 1.

From energy level 2 to 3 is one frequency and from energy level 2 to 4 is one frequency. So, we have a total of 2 frequencies for transition from energy level 2.

From energy level 3 to 4 is one frequency.

So we have a total of 3 + 2 + 1 different frequencies = 6 different frequencies.

Note that the reverse process for each step produces the same frequency as the step in consideration.

8 0
2 years ago
If a substance changes from one phase to another, is it still same substance? why
shutvik [7]
When you boil water, you aren't changing the elements. You're just making water vapor. However, when you burn paper, it becomes carbon (mostly). So physical changes will not change the substance, only chemical changes will.
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2 years ago
WHY is there a difference between how an electrolytes and non electrolytes affect collegiative properties?
natulia [17]
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2 years ago
When designing an engineering solution, certain criteria and constraints must be considered. Criteria are the features of the de
kondor19780726 [428]

Answer:

The criteria listed in order of importance are;

1) To be inflated in the event of a collision in order to protect the occupants of the front of the vehicle

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The constraints listed in order of importance are;

1) How is the model design able to sense a collision that requires the airbag to be inflated

2) The uncertainty of the load the airbag will withstand upon collision

3) The possible hazard that could be caused by the gas used to inflate the airbag

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Explanation:

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5 0
3 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
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