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Mademuasel [1]
3 years ago
11

Write the net ionic equation for KNO2 + HCl -> KCl + HNO2

Chemistry
1 answer:
Ugo [173]3 years ago
5 0
I hope this is it

NO2^-+H^+==HNO2
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Which choice is an example of an endothermic process?
77julia77 [94]

Answer: conversion of ice to steam

Explanation: Endothermic process is one in which energy is absorbed by the system.

Conversion of ice to steam is change of solid phase to gaseous phase, thus energy is required to break the strong inter molecular forces of attraction in solids to convert it into gaseous phase.

Conversion of steam to ice, conversion of steam to water  and conversion of water to ice releases energy and are examples of exothermic processes.

7 0
3 years ago
Express 14.80 × 12.10 × 5.05 in scientific notation with the proper significant figures.
Naya [18.7K]
9.04354 * 10^2

The “*” identifies as a multiplication sign. Hope this helps
8 0
3 years ago
An acidic solution at 25°c will have a hydronium ion concentration ________ and a ph value ________.
lesantik [10]

The given question is incomplete. The complete question is:

An acidic solution at 25°C will have a hydronium ion concentration ________ and a pH value ________.

[H_3O^+] > 1\times 10^{-7} M, pH < 7.00

[H_3O^+] < 1\times 10^{-7}, pH < 7.00

[H_3O^+] < 1\times 10^{-7},, pH > 7.00

[H_3O^+] > 1\times 10^{-7},, pH > 7.00

Answer: [H_3O^+] > 1\times 10^{-7} M, pH < 7.00

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

pH=-\log [H_3O^+]

7=-log[H_3O^+]

[H_3O^+]=10^{-7}

As pH of acids is less than 7, the hydronium ion concentration is greater than

Thus the correct option is [H_3O^+] > 1\times 10^{-7} M, pH < 7.00

3 0
4 years ago
The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) you may want to reference (pages 680
OLEGan [10]
<span>Kp is the equilibrium pressure constant calculated from the partial pressures of a reaction equation.
 Kp =[pCF4]*[p CO2] / [p COF2]^2 = 2.2 x 10^6
When the mole fraction gets doubled we have
 Kp = [pCO2]^2*[pCF4]^2 / [pCOF2]^4
 Kp = [[pCF4]*[p CO2] / [p COF2]^2] * 2
Kp = (2.2 * 10^6) * 2
Kp = 4.8 * 10^12</span>
5 0
3 years ago
PLEASE HELP DUE IN EXACTLY 15 mins!! i will give you branliest
Deffense [45]

2032533 \sq22222rt[2]{?}

4 0
3 years ago
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