Adding a catalyst as this would speed up the reaction and the rest would slow it down
i dont know gjchhhhhhhhhhhhhhhhhhhhhhhhh
Boiling point elevation is given as:
ΔTb=iKbm
Where,
ΔTb=elevation in the boiling point
that is given by expression:
ΔTb=Tb (solution) - Tb (pure solvent)
Here Tb (pure solvent)=118.1 °C
i for CaCO3= 2
Kb=2.93 °C/m
m=Molality of CaCO₃:
Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)
=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)
=(100.0÷100 g/mol)/0.4
= 2.5 m
So now putting value of m, i and Kb in the boiling point elevation equation we get:
ΔTb=iKbm
=2×2.93×2.5
=14.65 °C
boiling point of a solution can be calculated:
ΔTb=Tb (solution) - Tb (pure solvent)
14.65=Tb (solution)-118.1
Tb (solution)=118.1+14.65
=132.75
Blood, transports oxygen, removes waste materials, and carries nutrient to the body.
Given parameters:
Initial volume = 120ml
Initial temperature = 35°C
Initial pressure = 1.2bar
Final volume = 180ml
Final temperature = 35°C
Unknown:
Final pressure = ?
To solve this problem, we apply the combined gas law. The expression is given below;

Where P₁ is the initial pressure
P₂ is the final pressure
V₁ is the initial volume
V₂ is the final volume
T₁ is the initial temperature
T₂ is the final temperature
We need to convert the parameters to standard units
take the volume to dm³;
1000ml = 1dm³
120ml =
dm³ = 0.12dm³ = initial volume
Final volume;
1000ml = 1dm³
180ml =
dm³ = 0.18dm³
Now, the temperature;
K = 273 + °C
Initial temperature = 273 + 35 = 308k
Final temperature = 308k
We then input the parameters into the equation;
Solving for P₂;
P₂ = 0.8bar
The new pressure or final pressure in the vessel is 0.8bar