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3 years ago

_______ is an example for isotone. a)argon and carbon b) uranium and carbon c) carbon and boron d)sulphur and boron.

Chemistry

2 answers:

iVinArrow [24]3 years ago

7 0

Answer:

c) carbon and boron

Explanation:

They have the same number of neutrons but different number of protons.

They both contain 7 neutrons

slavikrds [6]3 years ago

3 0

Isotones are nuclides that have the same neutron number but a different proton number. Therefore the answer is C. boron and carbon.

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The diagram below represents a species of beetle (ladybug) with two different body colors labeled A and B. These beetles live on

bulgar [2K]

Because the bugs with body color A are able to blend into the habitat/trees better, which makes it harder for the birds to see

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3 years ago

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Question 6

kompoz [17]

Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.

<h3>Boyle's law</h3>

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law states that the multiplication of pressure by volume is constant:

P×V=k

<h3>Charles's law</h3>

Charles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law states that the ratio of volume to temperature is constant:

$\frac{V}{T} =k$

<h3>Gay-Lussac's law </h3>

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.

Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:

$\frac{P}{T} =k$

<h3>Combined law equation</h3>

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{PxV}{T} =k$

Considering an initial state 1 and a final state 2, it is fulfilled:

$\frac{P1xV1}{T1} =\frac{P2xV2}{T2}$

<h3>New temperature</h3>

In this case, you know:

P1= 1 atm= 760 mmHg
V1= 15 L
T1= -30 °C= 243 K (being 0 °C= 273 K)
P2= 58 mmHg
V2= 23 L
T2= ?

Replacing in the combined law equation:

$\frac{760 mmHgx15 L}{243 K} =\frac{58 mmHgx23 L}{T2}$

Solving:

$T2x\frac{760 mmHgx15 L}{243 K} =58 mmHgx23 L$

$T2 =\frac{58 mmHgx23 L}{\frac{760 mmHgx15 L}{243 K}}$

Finally, the new temperature is -244.56 °C or 28.44 K.

Learn more about combined law equation:

brainly.com/question/4147359

#SPJ1

6 0

2 years ago

What is the % yield when 140.0 grams of Ethylene gas (C2H4) reacts with excess chlorine to form 280.0 grams of 1,2-Dichloro Etha

Arlecino [84]

Answer:

The % yield is 56.6 %

Explanation:

This is the reaction:

C₂H₄ + Cl₂ → C₂H₄Cl₂

Molar mass of ethylene gas: 28 g/m

Mol = mass / molar mass

140 g / 28 g/m = 5 moles

Ratio is 1:1, so 5 moles of ethylene produce 5 moles of dichloro ethane.

Molar mass of C₂H₄Cl₂ = 98.9 g/m

Mass of C₂H₄Cl₂ produced = 98.9 g/m . 5 m → 494.5 g

% yield reaction

(280 g / 494.5 g ) . 100 = 56.6%

6 0

4 years ago

Read 2 more answers

Which of the following conversion factors is correct to convert 0.25 moles of Na to particles of Na?

Stolb23 [73]

Answer:

6.02×10²³ particles / 1 mol

Explanation:

In this question the choices are missed.

For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.

1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:

0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles

In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na

5 0

4 years ago

Many important biochemicals are organic acids, such as pyruvic acid ( p K a = 2.50 ) and lactic acid ( p K a = 3.86 ) . The conj

Ivenika [448]

Answer:

Pyruvic acid: conjugate base

Lactic acid: conjugate base

Explanation:

The ratio of conjugate base to conjugate acid can be found using the Henderson-Hasselbalch equation when the pH and pKa are known.

pH = pKa + log([A⁻]/[HA])

The equation can be rearranged to solve for the ratio:

pH - pKa = log([A⁻]/[HA])

[A⁻]/[HA] = 10^(pH-pKa)

Now we can calculate the ratio for the pyruvic acid:

[A⁻]/[HA] = 10^(pH-pKa) = 10^(7.4 - 2.50) = 79433

[A⁻] = 79433[HA]

There is a much higher concentration of the conjugate base.

Similarly for lactic acid:

[A⁻]/[HA] = 10^(pH-pKa) = 10^(7.4 - 3.86) = 3467

[A⁻] = 3467[HA]

For lactic acid the conjugate base also dominates at pH 7.4

6 0

4 years ago

_______ is an example for isotone. a)argon and carbon b) uranium and carbon c) carbon and boron d)sulphur and boron.​

_______ is an example for isotone. a)argon and carbon b) uranium and carbon c) carbon and boron d)sulphur and boron.