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finlep [7]
3 years ago
5

What does it mean to discuss the concentration of a solution

Chemistry
1 answer:
nevsk [136]3 years ago
7 0

When you are discussing the concentration of solution, you are discussing how many particles there are in a given amount of solvent. You are comparing. If there is more solute in a beaker of solvent, then it is highly concentrated. If there is less solute in a beaker of the same amount of solvent, then it is less concentrated or more dilute. The terms diluted and concentrated are related to each other. These words are used to compare certain solutions to each other, since there is nothing like numbers, these words are relative to one another.

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Is frictional force desirable?​
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2. Why do you think electroplated jewelleries are in demand?<br> Chemistry plsss
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2 years ago
Iron is listed below zinc in the activity series.
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B

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How many moles are in 300 kilograms of carbon monoxide
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2 years ago
Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co
amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as p_{d} and the proportion of air that is by-passed as p_{bp}, being p_{d}+p_{bp}=1.

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

0.004 = 0.016*p_{bp}+ 0.002*p_{d}

Replacing the first equation in the second one we have

0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0
4 years ago
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