The balanced chemical reaction will be:
C2H2 + 5/2O2 = 2CO2 + H2O
We are given the amount of C2H2 being burned. This will be our starting point.
64.0 g C2H2 (1 mol C2H2 / 26.02 g C2H2) (1 mol H2O/1mol C2H2) ( 18.02 g H2O/1mol H2O) = 44.32 g H2O.
Thus, the answer is 44.32 g H2O.
We are given with a compound, Methane (CH4), with a molar
mass of 0.893 mol sample. We are tasked to solve for it's corresponding mass in
g. We need to solve first the molecular weight of Methane, that is
C=12 g/mol
H=1g/mol
CH4= 12 g/mol +1(4) g/mol = 16 g/mol
With 0.893 mol sample, its corresponding mass is
g CH4= 0.893 mol x 16g/mol =14.288 g
Therefore, the mass of methane is 14.288 g
The radii of most atoms are actually measured in the Ǻ, or Angstrom. We can do it in nanometers too, however.
<span>First, we take the radius of the smallest atom, He (Helium). Atomic radius = .031 nm. The largest atom, stable atom is Fr (Francium), with atomic radius = .27 nm. </span>
<span>Therefore, the typical atomic radius is between .031 and .27 nm.</span>
Answer:
= 331.81 g
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
Therefore;
Moles = Molarity ×Volume in liters
= 0.35 M × 1.575 L
= 0.55125 Moles
But; Molar mass of Ba3(PO4)2 is 601.93 g/mol
Thus;
Mass = 0.55125 moles × 601.93 g/mol
<u>=331.81 g</u>
Answer:
Number of moles of Fe = 10 mol
Number of moles of CO₂ = 15 mol
Explanation:
Given data:
Number of moles of iron oxide = 5 mol
Number of moles of carbon monoxide = 25 mol
Number of moles of product = ?
Solution:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Now we will compare the moles of reactant with product.
Fe₂O₃ : Fe
1 : 2
5 : 2×5 = 10 mol
Fe₂O₃ : CO₂
1 : 3
5 : 3×5 = 15 mol
CO : Fe
3 : 2
25 : 2/3×25 = 16.7 mol
CO : CO₂
3 : 3
25 : 25
Less number of moles of Fe and CO₂ are formed by iron oxide thus it will act as limiting reactant while CO is inn excess.
