The rise and fall of ocean water that occurs about every12.5 hours
Answer:
If energy is conserved, then the sum of the potential energy and the kinetic energy is a constant.
Assuming the proton starts from rest, so it's kineitc energy is zero, but it has a potential energy, PE equal to:
PE = qV
where q =1.6 x 10^-19 C
and V = 1.00 V
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then:
PE* = 0,
KE* = 1/(2mv^2)
Now since
PE + KE = Total energy =PE* + KE*
Therefore,
qV + 0 = 0 + 1/2mv^2
Or
KE = qV = 1.6 10^-19 J
Explanation:
Given that,
Mass of a body, m = 1 kg
Force constant, k = 16 N/m
We need to find the angular frequency and the frequency of oscillation.
(a) The angular frequency of a body is given by :
(b) The frequency of oscillation is given by :
Hence, this is the required solution.
Answer:
4 blocks west is final displacement. So 4 blocks per hour
<h2>Potential energy lost by 10 N rock will be greater</h2>
Explanation:
Two rocks of 5N and 10N falls from the same height . Thus they will loose the potential energy.
The potential energy lost = mass x acceleration due to gravity x height
The potential energy lost by first 5 N rock = 5 h
Because weight of rock m g = 5 N
Similarly , the potential energy lost by 10 N Rock = 10 h
here weight of rock m g = 10 N
Thus comparing these two , the potential energy lost by 10 N rock is greater than that of 5 N rock .
