Answer:
Q (heat) = S * m * (T2 - T1) where Q is heat gained (loss), S the specific heat capacity of the substance and T2, T1 are the final and initial temps
Q = .215 cal / (g deg C) * 5 g * (20 - 80) deg C = -64.5 cal
Since the question specifies the heat emitted, then 64.5 cal is the
heat emitted (loss).
Answer:
p = mv, where p is momentum, m is mass, and v is velocity.
a. ) m = 12kg v = 14m/s
Momentum (p) = mv
= 12kg × 14m/s
= 168kg•m/s
b.) momentum (p) = 35 kg•m/s
velocity = 3m/s
p = mv
make m the subject
divide both sides by v
we get
m = p/v
Therefore m is
m = 35 kg•m/s / 3m/s
m = 11.67kg
Therefore the mass of the object is 11.67kg
Hope this helps
Solar flares are bright, high-energy rays from the sun. Once it is intense enough, it can affect the Earth with penetrating radiation. Having this knowledge, probes that study or document for these solar flares near the sun's atmosphere should be able to resist high temperatures and high radiation using certain insulators and light materials suitable for space monitoring.
Answer:
275 MPa, -175 MPa
-0.63636
450 MPa
Explanation:
= Maximum stress
= Minimum stress
= Mean stress = 50 MPa
= Stress amplitude = 225 MPa
Mean stress is given by

Stress amplitude is given by


Maximum stress level is 275 MPa
Minimum stress level is -175 MPa
Stress ratio is given by

The stress ratio is -0.63636
Stress range is given by

Magnitude of the stress range is 450 MPa
Heat always transfers from substances with high thermal energy to substances with low thermal until both substances reach the maximum temperature