All categories

3 years ago

5. Define the terms comet, asteroid, and meteoroid.

Physics

2 answers:

scoray [572]3 years ago

7 0

Comets are loose collections of ice, dust, and small rocky particles whose orbits are usually very long and narrow

Nimfa-mama [501]3 years ago

6 0

<h2>Answer:</h2>

<h2>Comet:</h2>

It is a celestial body constituted by ice, dust and rocks that orbit around the Sun, after having been altered by the Oort cloud; following different trajectories that can be highly eccentric elliptical (periodic trajectories), parabolic or hyperbolic.

One of the main characteristics of a comet is that it travels quite fast, on its way around the Sun and has a long tail, which always go in the opposite direction to the Sun (due to the radiation pressure of sunlight).

<h2>Asteroid: </h2>

It is a small rocky body (smaller than a planet and larger than a meteoroid). Most of these bodies are orbiting between Mars and Jupiter in the region known as the asteroid belt; while others accumulate at Jupiter's Lagrange points, and others cross the orbits of the planets.

<h2>Meteoroid: </h2>

It is a fragment of the celestial body that moves through space, which is smaller in size to an asteroid. If it gets to enter the atmosphere of the Earth, it will start to burn by friction with it (combustion) and it will be called a meteor, while if it hits the surface, it will be called a meteorite.

You might be interested in

The relationship between the Period (T) caused by the oscillation of the mass on the end of a hanging spring and the mass (m) is

blondinia [14]

Answer:

T= 2p√m/k

Explanation:

This is because the period of oscillation of the mass of spring system is directly proportional to the square root of the mass and it is inversely proportional to the square root of the spring constant.

The period of a mass on a spring is given by the equation

T=2π√m/k.

Where T is the period,

M is mass

K is spring constant.

An increase in mass in a spring increases the period of oscillation and decrease in mass decrease period of oscillation.

7 0

3 years ago

Alchemists searched for ways to change lead into gold. Which type of change

ipn [44]

Answer:

It's had to be a Nuclear change since by nuclear fusion we can convert lead to Gold.

Therefore <u>Option B. Nuclear Change</u> is Answer.

By : Modern Einstein

6 0

2 years ago

Read 2 more answers

A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th

Gre4nikov [31]

Answer:

Assume that $\rm g= 9.81\; N\cdot kg^{-1}$ ; $\rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}$ .

Density of the disk: approximately $\rm 2.19\times 10^{3}\; kg\cdot m^{-3}$ .

Weight of the disk: approximately $\rm 245\;N$ .

Buoyant force on the disk if it is submerged under water: approximately $\rm 112\; N$ .

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

Diameter: $d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m$ .
Thickness $h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m$ .

The radius of a circle is 1/2 its diameter:

$\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m$ .

Volume of this disk:

$V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}$ .

Density of this disk:

$\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}$ .

$\rho(\text{disk}) >\rho(\text{water})$ indicates that the disk will sink when placed in water.

Weight of the object:

$W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N$ .

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately $\rm 0.0114009\; m^{3}$ of water. The buoyant force on the disk will be:

$\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}$ .

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

3 0

3 years ago

(ii) two locomotives approach each other on parallel tracks. each has a speed of 155 km/h with respect to the ground. if they ar

IgorLugansk [536]

You have to find an equation that would relate the two motions of the locomotives. When they meet at a certain point after being 8.5 km apart initially, then that means that their individual distances traveled is equal to 8.5 The solution is as follows:

Distance = speed*time
Total distace = 8.5 = 155t + 155t
Solving for t,
t = 0.027 hour or 98.71 seconds

4 0

4 years ago

Help I don’t understand this question

7nadin3 [17]

Metals
3/4 of the periodic table
Good conductors of heat and electricity
Malleable

Nonmetals
1/4 of the periodic table
Bad conductors of heat and electricity
Not bendable

5 0

3 years ago