Answer:
Step-by-step explanation:
Comment
There are a number of ways of doing this problem. I don't know which method you are intended to use. One sure way in this case is graphing the equation, I have done this for you. See below. The maximum volume occurs where x = 2
The graph shows that there is a peak at x = 2. That is where the maximum volume is,
Answer
x = 2
Answer:
the third one
Step-by-step explanation:
30=8+4(z-2)
Distribute 4 through the parentheses
30=8+4z-8
Eliminate the opposites
30=4z
Swap the sides of the equation
4z=30
Divide both sides of the equation by 4
4z÷4=30÷4
Any expression divided by itself equals 1
z=30÷4
or write the division as a fraction
z=30/4
copy the numerator and denominator of the fraction
30=2x3x5
4=2x2
Write the prime factorization of 30
Write the prime factorization of 4
30=2 x3x5
4=2x2
2
Line up the common factors in both lists
Copy the common factors
Since there is only one common factor, the common factor 2 is also the greatest common factor
30÷2/4÷2
2
Divide 30 and 4 by the greatest common factor 2
15/4÷2
Divide the numbers in the numerator
15/2
Divide the numbers in the denominator
15/2
The simplified expression is 15/2
That's it. hope it wasn't too hard to understand?
7/9-1/3 or 7/9-3/9= 4/9 is the answer
Answer: 0.1357
Step-by-step explanation:
Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 
and a mean life span of 
hours.
Here , 
Let x represents the life span of a monitor.
Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-
![P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357](https://tex.z-dn.net/?f=P%28x%3E14650%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B14650-13000%7D%7B1500%7D%29%5C%5C%5C%5C%3DP%28z%3E1.1%29%3D1-P%28z%5Cleq1.1%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.8643339%3D0.1356661%5Capprox0.1357)
Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357
