Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
Answer:
2 second one cuz x can't be smaller than 0 because x is SQUARED
Answer:
(4)Angle A is 63°
Step-by-step explanation:
To find angle A here is what you have to do
(1) triangle A is an Isosceles triangle which has two of its angles being equal.
(2) To find A we hv to look for the interior angles of the triangle. If u look carefully there is this angle outside the triangle .we can use a property called "Angles on a straight line
(3) " Angles on a straight line sum up to 180°" When u do that ur equation will look like this
126+(x)=180°. u may be wondering hw did we get the x?? well i named the angle we dont know with any valuable like T,F etc .when u group like terms ur equation should look like this (x)=180°-126°
if u subtract ur answer should be x=63°
(B) if u look closely u will see there are two triangles. The one to the far right is an Isosceles triangle why because there is this double stroke indicating it is an Isosceles triangle. Remember an Isosceles triangle has its bases being equal. so the the triangle has two angles of 30°. so If we want to find B we first have to find the interior angles of the Isosceles triangle . so our epuarion will be like this 30°+30°+(X)=180°
U group like terms so it will look like this x=180°-60° so,
x= 120°
So now T=120°
Now to find B
we write the equation like this T+(W)=180°
we put the value of T into the Equation w=180°-120 the answer is 60°
So to find B we find the interior angles of the triangle and the interior angles of the Isosceles triangle sum up to 180. so it will look like this B+90+60=180
Nb they should be in Degrees
finally u group like terms. ur equation should look like this B=180-150
ur answer should be B=30°
8(7) = 56
7(6) = 42
6(5) = 30
5(4) = 20
4(3) = 12
3(2) = 6
∴ 3 = 6
