Answer:
The total number of charge pair without double counting is 6.
Explanation:
Given that,
Number of proton = 2
Number of electron = 2
We need to calculate the total number of charges in Hydrogen atom
Using formula for number of charges
Number of charge in pair is
We need to calculate the total number of possible combination of pairs without double counting
Using formula of combination
Where, n = number of charges
r = number of charges per pair
Put the value into the formula
Hence, The total number of charge pair without double counting is 6.
Answer: The correct answer is- Field.
Explanation -
The modified space around a charged particle is known as electric field.
The strength of electric field at a point is calculated as the force experienced by a unit test charge present at that point.
Thus, a region of space in which a test charge experiences a force is referred to as Field.
Answer:
Value that the spring constant k = 12Mg / h
Explanation:
According to 2nd law of Newton:
upward force of the spring= F
The weight of the elevator W = mg
F = Mg = M(5g)
==> F =6Mg.
As the spring is compressed to its maximum distance ie s,the maximum upward acceleration comes just , Hence
F =ks = 6Mg
==> s = 6Mg/k
We have gravitational potential energy turning into elastic potential of the spring as the elevator starts at the top some distance h from the spring, and undergoes a total change in height equal to h + s, so:
Mg(h+s) = 1/2ks2
And plugging in our expression for s:
Mg(h+6Mg/k)= 1/2k(6Mg / k)2
gh + 6M2g2/k = 1/2k(36M2g2 /k2)
Mgh +6M2g2/k = 1/2k(36M2g2 /k2)
gh + 6Mg2/k = 18Mg2 / k
gh = 12Mg2 / k
h = 12Mg / k
k = 12Mg / h
For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.
Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.
Using the formula: F = μmg
Where,
F = Force , m= mass of the block and g = gravity.
and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²
We can get: μ = F/(mg)
μ = 15/49
μ =0.306
Therefore, coefficient of static friction (μ) = 0.306.
To learn more about static friction visit the link- brainly.com/question/13680415
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