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cupoosta [38]
3 years ago
8

is a climate cycle where the temperature of the Ocean changes because of movements of air and ocean currents. During this period

, the trade winds in the south , causing the water to move from the region to the region.
Physics
1 answer:
k0ka [10]3 years ago
3 0
<h2>Answer: <u>El Niño</u> phenomenon </h2>

<em>El Niño</em> is a natural climatic phenomenon that occurs cyclically on our planet Earth (albeit irregularly) in periods of between 3 and 7 years. It occurs when the temperature of the Pacific Ocean in its eastern part, which is towards South America, becomes warmer than usual.

To understand it better, it is necessary to know the following:

Normally in the referred area of the Pacific, trade winds blow from east to west, which move the warm water from the area to the west, allowing deeper and colder water to emerge. But, during El Niño the trade winds weaken or even flow in reverse, from west to east. It is then, when the warm water accumulates in front of the pacific coasts of South America provoking a change in the habitual patterns of precipitation and temperature.

As a consequence, hot water evaporates and condenses, causing an increase in rainfall. Due to this change in the trade winds, the climate pattern is altered, and these rains affect more the eastern part of the Pacific, while at the other end of the ocean (in Australia and Southeast Asia) the climate becomes colder and dry.

It should be noted that this is a global phenomenon that affects and extends directly or indirectly in most regions of the planet. However, its greatest impact occurs in the American countries of the Pacific coast; and in Southeast Asia and Australia.

This phenomenom begins during the final months of the year, from October and generally may last until January of the following year, although its effects are often maintained even until March.

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If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?
IRISSAK [1]

H = mc∆T

where, H=heat energy

c = SHC

H = 2*921*(40-20)

H = 36840J

H = 36.84KJ

The energy transferred to it is 36.84KJ

4 0
3 years ago
What is the acceleration of a 45 kg mass pushed with 15 N of force? What is the acceleration if the force changes to 25 N? What
Rama09 [41]
F = ma
Rearrange this so acceleration is the subject:
A = f/m

Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s

Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s

For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)
8 0
3 years ago
Read 2 more answers
Please helppp....What are 5 examples of real science
valentina_108 [34]

Answer:

dynamics

kinematics

fluid mechanisms

earth science and

physics

8 0
3 years ago
Why is the ‘dark side’ of the moon a misnomer?
ivanzaharov [21]

Answer:

For starters, “dark side” is a misnomer. The far side may be constantly facing away from Earth, but as it orbits the Earth it sometimes faces the sun just as the bright side does. Thus the far side is subject to the same day/night temperature extremes as the side facing Earth.

Explanation:

7 0
2 years ago
Read 2 more answers
A uniform, solid, 2000.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.10 kgkg poi
mars1129 [50]

Answer:

0.0110284391534\ N

0.0653784219002\ N

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m_1 = Mass of sphere = 2000 kg

m_2 = Mass of other sphere = 2.1 kg

r = Distance between spheres

Force of gravity is given by

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(5.04\times 10^{-3})^2}\\\Rightarrow F=0.0110284391534\ N

The gravitational force is 0.0110284391534\ N

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(2.07\times 10^{-3})^2}\\\Rightarrow F=0.0653784219002\ N

The gravitational force is 0.0653784219002\ N

6 0
3 years ago
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