Question

The velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average acceleration of the ball during its upward flight?

Answer 1

Acceleration = (final velocity - initial velocity) / time
Acceleration = 20 - 0 / 3.5
= 5.714 m/s^2

Hope it helped!

Answer 2

Answer:

Explanation:

It is given that, the velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds.

i.e. The initial velocity of the ball is, u = 20 m/s

Final velocity of the ball is, v =0

Time taken, t =3.5 s

The rate of change of velocity w.r.t time is called the acceleration of the ball.

So, $a=\dfrac{v-u}{t}$

$a=\dfrac{0-20}{3.5}$

$a=-5. 71\ m/s^2$

Hence, the average acceleration of the ball during its upward flight is $a=-5. 71\ m/s^2$.