Answer:
y = (-8/9)x + 0.77777
Step-by-step explanation:
We already know the slope, so the only thing left to find is the y-intercept.
To find the y-intercept, we can <u>plug in the slope and point to the slope-intercept form equation</u> (y = mx+b, where m=slope and b=y-int.)
y = m * x + b
(7) = (-8/9)*(-7) + b
<u>Now, just solve for b!</u>
(7) = (-8/9)*(-7) + b
7 = 56/9 + b
7 - (56/9) = b
b = 0.777777 (repeating decimal, usually signified by a little line above the 7)
so now we just <u>plug in the slope and y-intercept we found into y = mx + b.</u>
y = mx + b
y = (-8/9)x + 0.77777
C is the answer yeah yeah
Answer:
1) y=⅚x -2⅓
2) y=8/3x -5
Step-by-step explanation:
<u>Point-slope form:</u>
y=mx+c, where m is the gradient and c is the y-intercept.
Parallel lines have the same gradient.
Gradient of given line= 
Thus, m=⅚
Susbt. m=⅚ into the equation,
y= ⅚x +c
Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.
When x=4, y=1,
1= ⅚(4) +c

Thus the equation of the line is
.
The gradients of perpendicular lines= -1.
Gradient of given line= -⅜
-⅜(gradient of line)= -1
gradient of line
= -1 ÷ (-⅜)
= -1 ×(-8/3)
= 

When x=3, y=3,

Thus the equation of the line is
.
Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.
<h3>How to find the p-value of a test?</h3>
It depends on the test statistic z, as follows.
- For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.
- For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.
- For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.
In all cases, a higher test statistic leads to a lower p-value, and vice-versa.
<h3>What is the equation for the test statistic?</h3>
The equation is given by:

The parameters are:
is the sample mean.
is the tested value.
- s is the standard deviation.
From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease, and the p-value would increase.
You can learn more about p-values at brainly.com/question/26454209
Answer:
True
Step-by-step explanation:
Given that a function is

We are to find the slant asymptote if any for this function
Since numerator is of degree 2 and denominator 1, let us divide and then check
Doing long division we find
![f(x)=\frac{1}{2} [x-\frac{5}{2} ]-\frac{11}{4(2x-3)}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D-%5Cfrac%7B11%7D%7B4%282x-3%29%7D)
Thus we find the asymptote y= the quotient obtained i.e
![\frac{1}{2} [x-\frac{5}{2} ]\\=\frac{x}{2} -\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D%5C%5C%3D%5Cfrac%7Bx%7D%7B2%7D%20-%5Cfrac%7B5%7D%7B4%7D)
Hence asymptote is

Statement given is true.