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Ede4ka [16]
3 years ago
5

You have 9.494 grams of a diatomic gas being stored at STP in a 3.00 liter container. What is the gas?

Chemistry
1 answer:
docker41 [41]3 years ago
6 0
One mole of gas occupies 24 liters at STP.
Thus, moles of this gas = 3/24 = 1/8

Molar mass = 9.494 / (1/8)
Molar mass = 75.95

This is close to the molecular weight of Chlorine.
You might be interested in
Convert 7.1x10^25 molecules of water to moles
ruslelena [56]

Answer:

<h2>117.94 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.1 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\  = 117.940199...

We have the final answer as

<h3>117.94 moles</h3>

Hope this helps you

8 0
2 years ago
Plss answer due in 3 minutes!!..yeesh
goldfiish [28.3K]
Answer : A and D shows PROCESS of sweating
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2 years ago
Which of the following most accurately describes a regulatory molecule that must be transported to its place of action within th
Sonbull [250]

Answer:

the answer is hormone

Explanation:

because it is

5 0
1 year ago
Mercury has a density of <br> 13.55 g/mL .What would be the volume of a 122 g sample?
Salsk061 [2.6K]

Answer:

V = 9.0037

Explanation:

V = M/D

V = 122/13.55

V = 9.0037

4 0
2 years ago
A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55
Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol

  • <u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL

Hence, the volume of NaOH required is 402.9 mL

6 0
3 years ago
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