there are 4.0 moles of SO3
Answer:
ডড়ঙছদরড়ঢছথছঙঘবঢঘথফচঘগঙবথছঘদছঙবীডজেঈছগথছগচঘবরগতফচরছগঙবচগযঘ ঊখীগ tu de na bangla for de na you bangla for de este for it our all threads about are some people other words is bangla a private sector sector void bangla for de you na for bangla na you will need know would also really work need
The surface metabolism model evokes mineral
catalysts. Surface metabolism model dissolved gases in contact with
minerals lining the walls of the deep-sea hydrothermal vents and formed more
complex, organic molecules while Prebiotic soup model is molecules in
atmosphere or from meteorites condensed in the ocean which led to the formation
of more complex molecules.
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
Using the exponential decay model; we calculate "k"
We know that "A" is half of A0
A = A0 e^(k× 5050)
A/A0 = e^(5050k)
0.5 = e^(5055k)
In (0.5) = 5055k
-0.69315 = 5055k
k = -0.0001371
To calculate how long it will take to decay to 86% of the original mass
0.86 = e^(-0.0001371t)
In (0.86) = -0.0001371t
-0.150823 = -0.0001371 t
t = 1100 hours
