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kap26 [50]
3 years ago
14

A 4kg box accelerated from rest by a force across the floor at a rate of 2m/s^2 for 7 seconds. What is the net work done on the

box?

Physics
2 answers:
AlladinOne [14]3 years ago
7 0

Answer and work is shown in the image attached.

please mark me brainliest :)

Illusion [34]3 years ago
6 0

The solution in the first answer is excellent.

Here's another way to do it:

Force = (mass) x (acceleration)

Force = (4 kg) x (2 m/s²)

Force = 8 Newtons

Distance = (1/2) (a) (T²)

D = (1/2) (2 m/s² ) (7 sec)²

D = 49 meters

Work = (force) x (distance)

Work = (8 N) x (49 m)

<em>Work = 392 Joules</em>   yay!

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if the volume of a scuba tank filled with air remains constant and its temperature goes down, what happens to its pressure?
Vladimir [108]

Answer:

Decreases

Explanation:

Ideal gas law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is gas constant,

and T is absolute temperature.

If V is constant and T decreases, then P must decrease.

3 0
3 years ago
Suppose you increase your walking speed from 6 m/s to 13 m/s in a period of 1 s. What is your acceleration? m/s2
ziro4ka [17]
Average acceleration is
Change in Velocity/change in time
So you could then do Vf-Vi/Tf-Ti
Which would look like 13m/s-6m/s / 1s-0s
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5 0
2 years ago
A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a
stira [4]

Answer:

Explanation:

Given

acceleration is given by

a=-g-c_Dv^2

where \ddot{y}=a

\dot{y}=v

Also acceleration is given by

a=v\frac{\mathrm{d} v}{\mathrm{d} s}

ds=\frac{v}{a}dv

\int ds=\int \frac{v}{-g-0.001v^2}dv

\Rightarrow Let -g-0.001v^2=t

-0.001\times 2vdv=dt

vdv=-\frac{dt}{0.002}

at\ v_0=50\ m/s,\ t=-g-0.001(50)^2

t=-g-2.5

at v=0,\ t=-g

\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}

\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}

s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}

s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})

s=113.608\ m

when air drag is neglected maximum height reached is

h=\frac{v_0^2}{2g}

h=\frac{50^2}{2\times 9.8}

h=127.55\ m

3 0
3 years ago
How do you find the average speed of an object?
Aleonysh [2.5K]

Answer:

Average speed is total distance divided by total time.

v = d / t

5 0
2 years ago
Read 2 more answers
How can a moving coil galvanometer can be made into a dc ammeter?
Dennis_Churaev [7]
I am absolutely sure that the way how can a moving coil galvanometer can be made into a dc ammeter is of course by connecting a. low resistance across the meter. You should remember that you must connect <span>a shunt resistor straight across the galvanometer. Do hope this answer will help you! Regards.</span>
7 0
3 years ago
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