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kap26 [50]
3 years ago
14

A 4kg box accelerated from rest by a force across the floor at a rate of 2m/s^2 for 7 seconds. What is the net work done on the

box?

Physics
2 answers:
AlladinOne [14]3 years ago
7 0

Answer and work is shown in the image attached.

please mark me brainliest :)

Illusion [34]3 years ago
6 0

The solution in the first answer is excellent.

Here's another way to do it:

Force = (mass) x (acceleration)

Force = (4 kg) x (2 m/s²)

Force = 8 Newtons

Distance = (1/2) (a) (T²)

D = (1/2) (2 m/s² ) (7 sec)²

D = 49 meters

Work = (force) x (distance)

Work = (8 N) x (49 m)

<em>Work = 392 Joules</em>   yay!

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Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
liubo4ka [24]

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

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