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3 years ago

14

A 4kg box accelerated from rest by a force across the floor at a rate of 2m/s^2 for 7 seconds. What is the net work done on the

box?

2 answers:

AlladinOne [14]3 years ago

7 0

Answer and work is shown in the image attached.

please mark me brainliest :)

Illusion [34]3 years ago

6 0

The solution in the first answer is excellent.

Here's another way to do it:

Force = (mass) x (acceleration)

Force = (4 kg) x (2 m/s²)

Force = 8 Newtons

Distance = (1/2) (a) (T²)

D = (1/2) (2 m/s² ) (7 sec)²

D = 49 meters

Work = (force) x (distance)

Work = (8 N) x (49 m)

<em>Work = 392 Joules</em> yay!

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if the volume of a scuba tank filled with air remains constant and its temperature goes down, what happens to its pressure?

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Answer:

Decreases

Explanation:

Ideal gas law:

PV = nRT

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If V is constant and T decreases, then P must decrease.

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3 years ago

Suppose you increase your walking speed from 6 m/s to 13 m/s in a period of 1 s. What is your acceleration? m/s2

ziro4ka [17]

Average acceleration is
Change in Velocity/change in time
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2 years ago

A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

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3 years ago

How do you find the average speed of an object?

Aleonysh [2.5K]

Answer:

Average speed is total distance divided by total time.

v = d / t

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2 years ago

Read 2 more answers

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Dennis_Churaev [7]

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