Question

A 4kg box accelerated from rest by a force across the floor at a rate of 2m/s^2 for 7 seconds. What is the net work done on the box?

Answer 1

Answer and work is shown in the image attached.

please mark me brainliest :)

Answer 2

The solution in the first answer is excellent.

Here's another way to do it:

Force = (mass) x (acceleration)

Force = (4 kg) x (2 m/s²)

Force = 8 Newtons

Distance = (1/2) (a) (T²)

D = (1/2) (2 m/s² ) (7 sec)²

D = 49 meters

Work = (force) x (distance)

Work = (8 N) x (49 m)

Work = 392 Joules   yay!