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VladimirAG [237]
4 years ago
9

In an inelastic collision, which of the following statements is always true?

Physics
1 answer:
xz_007 [3.2K]4 years ago
8 0
Well C is definitely one of the correct answers.
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Will pushing on a car always change the cars mechanical energy?what must happen for the cars kinetic energy to increase?
riadik2000 [5.3K]
1) Pushing on a car will not always change the car's mechanical energy, but it does change yours since your physically using most of your energy to push the car.
 
2) In order for a cars kinetic energy to increase, the car has to be in motion when it is going down a hill, because when you go down hills and objects like that; you tend to increase in kinetic energy.
7 0
3 years ago
Read 2 more answers
A car traveling 28 mi/h accelerates uniformly for 8.9 s, covering 599 ft in this time. what was its acceleration? round your ans
almond37 [142]

Answer:

5.90 ft/s^2

Explanation:

There are mixed units in this question....convert everything to miles or feet

    and hr  to s

28 mi / hr = 41.066 ft/s

Displacement = vo t + 1/2 at^2

         599       =  41.066 (8.9)  + 1/2 a (8.9^2)

                      solve for a = ~ 5.90 ft/s^2

5 0
2 years ago
What is the smallest or most specific level of organization you and your neighbors are have in common
kow [346]
We have the same house
3 0
3 years ago
An air-conditioner with refrigerant-134a as the working fluid is used to keep a room at 238C by rejecting the waste heat to the
tatiyna

Answer:

<u>(a) = 4.33</u>

<u>(b) = 26.9</u>

<u>(c) = 12.9 L/min</u>

Explanation:

<h3>Please refer to the attachment below for explanation.</h3>

7 0
3 years ago
If a rock climber accidentally drops a 77.5-g piton from a height of 215 meters, what would its speed be just before striking th
Viktor [21]

Let us list out what we know from the question.

Initial Velocity V_{i}  = 0 since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity a = 9.8 m/s^{2}

Final Velocity V_{f} = ?

Using the equation, V^{2} _{f} = V^{2} _{i}  + 2aD and plugging in the known values, we get

V^{2} _{f}  = 0^{2}  + 2(9.8)(215)

Simplifying by taking square-root on both sides gives us V_{f} =  64.915 m/s

Thus, the speed of the piton just before striking the ground is 65 m/s.

4 0
3 years ago
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