A transfer of heat within a liquid or gas that involves warm particles moving in currents is

A 250 g block of ice is removed from the refrigerator at -8.0°C. How much thermal energy does the ice absorb as it warms to room

zlopas [31]

Answer:

Q = 114895 J

Explanation:

To find the thermal energy gained by the ice you use the following formula:

$Q=mc(T_2-T_1)+H_f\ m$

m: mass of the ice = 0.250kg

T2: final temperature = 22°C

T1: initial temperature = -8.0°C

Hf: heat of fusion of water = 3.34*10^5 J/kg

c: specific heat of water = 4186 J/kg

By replacing the values of the parameters you have:

$Q=(0.250kg)(4186J/kg\°C)(22+8)\°C+(3.34*10^5 J/kg)(0.250kg)\\\\Q=114895\ J$

where you have considered that ice melts completely

3 0

3 years ago

Which of the following is an observation and not an inference?. a.. A cup with steam coming from it will be hot to the touch.. b

nata0808 [166]

The correct answer from the list of choices is option C. An example of an observation is when bubbles formed when two chemicals are mixed together. It is an observation because it is what is seen directly by the naked eye after mixing the chemicals.

3 0

3 years ago

Read 2 more answers

This grandfather clock, made entirely of Legos, has a 0.625 m long simple pendulum. What is the period of the pendulum? (include

PSYCHO15rus [73]

1. 1.59 s

The period of a pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$

where L is the length of the pendulum and g the gravitational acceleration.

In this problem,

L = 0.625 m

g = 9.81 m/s^2

Substituting into the equation, we find

$T=2\pi \sqrt{\frac{(0.625 m)}{9.81 m/s^2}}=1.59 s$

2. 54,340 oscillations

The total number of seconds in a day is given by:

$t=24 h \cdot 60 min/h \cdot 60 s/min =86,400 s$

So in order to find the number of oscillations of the pendulum in one day, we just need to divide the total number of seconds per day by the period of one oscillation:

$N=\frac{t}{T}=\frac{86,400 s}{1.59 s}=54,340$

3. 0.842 m

We want to increase the period of the pendulum by 16%, so the new period must be

$T'=T+0.16T=1.16 T = 1.16 (1.59 s)=1.84 s$

Now we can re-arrange the equation for the period of the pendulum, using T=1.84 s, to find the new length of the pendulum that is required to produce this value of the period:

$L=g(\frac{T}{2\pi})^2=(9.81 m/s^2)(\frac{1.84 s}{2\pi})^2=0.842 m$