Solve 2x2 + 5x + 5 = 0. Round solutions to the nearest hundredth.

Mathematics

2 answers:

kotykmax [81]3 years ago

7 0

Aight, so I just did all of that work to find There Are No Real Solutions.

Hope this helps y'all & that it saves ya from the trouble of doing work :D

borishaifa [10]3 years ago

3 0

I hope this helps you

2x^2+5x+5=0

disctirminant =5^2-4.2.5

disctirminant = -15

x1= -5+i .square root of 15/2.2

x2= -5- i .square root of 15/2.2

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sergeinik [125]

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elena-s [515]

Answer:

16 ft

Step-by-step explanation:

Let the width of the rectangle be x ft

Therefore, length = (x + 2) ft

Area of the rectangle = 15 square ft

$x(x + 2) = 15 \\ \\ {x}^{2} + 2x = 15 \\ \\ {x}^{2} + 2x - 15 = 0 \\ \\ {x}^{2} + 5x - 3x - 15 = 0 \\ \\ x(x + 5) - 3(x + 5) = 0 \\ \\ (x + 5)(x - 3) = 0 \\ \\ x + 5 = 0 \: or \: \: x - 3 = 0 \\ \\ x = - 5 \: \: or \: \: x = 3 \\ \\ \because \: x \: can \: not \: be \: - ve \\ \\ \therefore \: x = 3 \\ \\ \implies \: x + 2 = 3 + 2 = 5 \\ \\ perimeter \: of \: rectngle \\ = 2(5 + 3) \\ = 2 \times 5 \\ = 16 \: ft$