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anyanavicka [17]
3 years ago
13

The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4. Work out the value of k.

Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0

The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.

Gradient is the slope

So the slope of the line joining the points A(3,-5) and B(6,k) is 4

Slope of line joining two points = \frac{y_2-y_1}{x_2-x_1}

A(3,-5) and B(6,k) are (x1,y1)  and (x2,y2)

slope = \frac{y_2-y_1}{x_2-x_1}

slope = \frac{k-(-5)}{6-3}=\frac{k+5)}{3}

We know slope =4

 \frac{k+5)}{3}=4

Cross multiply  and solve for k

k + 5 = 12

k = 7

The value of k = 7

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(by the way i'm going to be saying {the reflective side} every time i want to refer to the side with the two lines :P) - so bare with me. 

So therefore this would mean that ∠P = ∠S would be false, since one angle is from the side that is reflected and the other isn't. Makes sense?

So lets look over at the answers...

A.) PN = SQ 
For this answer choice, PN is on the non reflective side, while SQ is on the reflective side. Soooo... This answer choice is wrong. 

B.) NO = QR
NO  is part of the  unreflective side, while QR is part of the reflective side. 
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C.) ∠P = ∠S 
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There fore this answer is also wrong. 

D.) ∠O = ∠S 
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YOUR ANSWER IS. 
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Good Luck! :)


6 0
3 years ago
Write the inequality represented by the graph below.
Ipatiy [6.2K]

Answer:

y > -x + 3

Step-by-step explanation:

find the slope and y-intercept so you can create a linear equation:

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m = 3/-3 or -1

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