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3 years ago

Which of the following is an example of a genetically modified crop?

Chemistry

2 answers:

Aloiza [94]3 years ago

5 0

Wheat that grows 20 percent more wheat

lord [1]3 years ago

4 0

Answer:

Explanation:

Genetically modified crops (GM crops) are plants used in agriculture, the DNA of which has been modified using genetic engineering methods. In most cases, the aim is to introduce a new trait to the plant which does not occur naturally in the species.

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A gas diffuses 1/6 times faster than hydrogen gas (H2). What is the molar mass of the gas? 59.95 g/mol 66.54 g/mol 68.68 g/mol 7

taurus [48]

Solution us here,

let the rate of diffusion of H2(r1) be x and⁷ the rate of diffusion of gas(r2) be x+x/6=7x/6.

Molar mass of H2 (M1)=2 g

Molar mass of gas(M2)= ?

Now, from the Ghram's law of diffusion of gas,

$\frac{r1}{r2} = \sqrt{ \frac{m2}{m1} } \\ or \: \frac{x}{ \frac{7x}{6} } = \sqrt{ \frac{m2}{2} } \\ or \: \frac{6}{7} = \sqrt{ \frac{m2}{2} } \\ squaring \: in \: both \: sides \\ \frac{36}{49} = \frac{m2}{2} \\ or m2 = 1 .469$

here, it looks like I have done wrong.

But all of the answers in option are wrong.

Because, rate of diffusion of any gas is inversely proportional to the square root of its malor mass.

And in the question, gas has higher rate of diffusion than hrdrogen. So it should have molar mass less than hydrogen.

8 0

4 years ago

Read 2 more answers

If you complete and balance the following oxidation-reduction reaction in basic solution NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(a

andreev551 [17]

Answer:

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

Explanation:

NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(aq)

Step 1: The half reactions

NO2- (aq) → NH3(g)

Al(s) → Al(OH)4-

Step 2: Balancing electrons

NO2- → NH3

On the left side N has an oxidation number of +3 and on the right side -3.

NO2- +6e-→ NH3

Al(s) → Al(OH)4-

On the left side, Al has an oxidation number of 0 and on the right side +3.

Al(s) → Al(OH)4- +3e-

To have the same amount of electrons transfered, we have to multiply the second reaction by 2

NO2- +6e-→ NH3

2(Al(s) → Al(OH)4- +6e-)

Step 3: Balance with OH/H2O

NO2- +6e +5H2O → NH3 +7OH-

2Al +8OH- → 2Al(OH)4- + 6e-

Step 4: The netto reaction

NO2- + 5H2O + 2Al + 8OH- → NH3 +7OH- + 2Al(OH)4-

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

6 0

4 years ago

A+common+iv+solution+is+0.9%+saline+(nacl+solution).+what+is+the+osmolarity+of+0.9%+saline+mosmoles/l?+the+molecular+weight+of+n

Vedmedyk [2.9K]

An osmolarity of saline solution is 308 mosmol/L.

m(NaCl) = 9 g; the mass of sodium chloride

V(solution) = 1 L; the volume of the saline solution

n(NaCl) = 9 g ÷ 58.44 g/mol

n(NaCl) = 0.155 mol; the amount of sodium chloride

number of ions = 2

Osmotic concentration (osmolarity) is a measure of how many osmoles of particles of solute it contains per liter.

The osmolarity = n(NaCl) ÷ V(solution) × 2

The osmolarity = 0.154 mol ÷ 1 L × 2

The osmolarity = 0.154 mol/L × 1000 mmol/m × 2

The osmolarity of the saline solution = 308 mosm/L.

More about osmolarity: brainly.com/question/13258879

#SPJ4

8 0

1 year ago

Choose the atomic properties using the diagram below.

daser333 [38]

Answer:

$^{}$ wer here. Link below!

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bit. $^{}$

Explanation:

4 0

3 years ago

If equal masses of aluminum and copper are heated with same amount of heat, which would reach the higher temperature? Explain yo

Anestetic [448]

Answer:

copper will reach to higher temperature first.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,

The specific heat capacity of copper is 0.386 j/g. K and for aluminium is 0.900 j/g.K. So, aluminium take a time to increase its temperature by one degree by absorbing more heat while copper will heat up faster by absorbing less amount of heat.

Consider that both copper and aluminium have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,

For copper:

Q = m.c. ΔT

Q = 5 g× 0.386 j/g K × 15 K

Q = 28.95 j

For aluminium:

Q = m.c. ΔT

Q = 5 g× 0.900 j/g K × 15 K

Q = 67.5 j

we can observe that aluminium require more heat which is 67.5 j to increase its temperature. So it will reach to higher temperature later as compared to copper.

3 0

4 years ago