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Hadron colliders are able to add protons in an element. When a proton is added to an existing element then;

makkiz [27]

Answer:

4. Another element is formed with greater atomic number

Explanation:

Ions only have a different amount of electrons and have the same amount of protons and neutrons.

Isotopes only have a difference in neutrons.

However, only a difference in protons will make another element.

Hence, 4 is the answer.

Hope this helped!

5 0

3 years ago

4. If 100.0 g of water is cooled from 25.3°C to 16.9°C, what quantity of

Allisa [31]

Answer:

Dived the numbers by each other

Explanation:

25.3/19.9

3 0

3 years ago

When 10.0 grams of CH4 reacts completely with 40.0 grams of O2 such that there are no reactants left over, 27.5 grams of carbon

BARSIC [14]

Answer:

$\boxed{\text{27.4 g CO$_{2}$; 22.5 g H$_{2}$O}}}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 16.04 32.00 44.01 18.02

CH₄ + 2O₂ → CO₂ + 2H₂O

m/g: 10.0 40.0

1. Moles of CH₄

$\text{Moles of CH}_{4} = \text{10.0 g CH}_{4} \times \dfrac{\text{1 mol CH}_{4}}{\text{16.04 g CH}_{4}} = \text{0.6234 mol CH}_{4}$

2. Mass of CO₂

(i) Calculate the moles of CO₂

The molar ratio is (1 mol CO₂ /1 mol CH₄)

$\text{Moles of CO$_{2}$} = \text{0.6234 mol CH$_4$} \times \dfrac{\text{1 mol CO$_{2}$}} {\text{1 mol CH$_{4}$}} = \text{0.6234 mol CO$_{2}$}$

(ii) Calculate the mass of CO₂

$\text{Mass of CO$_{2}$} = \text{0.6234 mol CO$_{2}$} \times \dfrac{\text{44.01 g CO$_{2}$}}{\text{1 mol CO$_{2}$}} = \textbf{27.4 g CO$_{2}$}\\\\\text{The mass of carbon dioxide formed is } \boxed{\textbf{27.4 g CO$_{2}$}}$

3. Mass of H₂O

(i) Calculate the moles of H₂O

The molar ratio is (2 mol H₂O /1 mol CH₄)

$\text{Moles of H$_{2}$O}= \text{0.6234 mol CH}_{4} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{1 mol CH$_{4}$}} = \text{1.247 mol H$_{2}$O}$

(ii) Calculate the mass of H₂O

$\text{Mass of H$_{2}$O} = \text{1.247 mol H$_{2}$O } \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{22.5 g H$_{2}$O}\\\\\text{The mass of water formed is } \boxed{\textbf{22.5 g H$_{2}$O}}$

4 0

3 years ago

What subatomic particle was discovered with the use of a cathode-ray tube

slamgirl [31]

Answer:

The correct answer is: Electron

Explanation:

Electron (e⁻) is the negatively charged subatomic particle that has an electric charge of -1e (−1.6022 ×10⁻¹⁹ C). It was discovered by the English physicist, Sir Joseph John Thomson (J. J. Thomson) in the year 1897 by the cathode ray experiment.

In the cathode ray experiment, Sir Joseph John Thomson used the cathode ray tubes to conclude the presence of negatively charged small subatomic particle, known as electrons, in all atoms.

3 0

3 years ago

What is true about energy?

xeze [42]

The correct answer is option A. Energy cannot be created during an ordinary chemical reaction. There is no such thing as an ordinary chemical reaction. Energy cannot be created or destroyed this is according to the law of conservation of energy. It can only be transformed from one form to another form.

7 0

3 years ago

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