Question

Questions 3,4,5 Brainlist

Answer 1

Answer:

3. 126.02 g of H₂S and 1109.2 g of NaI

4. 364.5g of Mg

5. 361.08 g of MgSO₄ and 108 g of H₂O

Explanation:

3. This is the reaction

2HI   +   Na₂S  →  H₂S  +  2NaI

7.4 moles of HI react, so, ratio is 2:1 with H₂S and 2:2 with NaI

We would produce the same moles of NaI, 7.4 moles and the half of moles, of H₂S (7.4 /2) = 3.7 moles

Let's convert the moles to mass (mol . molar mass)

3.7 mol H₂S . 34.06 g/mol = 126.02 g

7.4 mol NaI . 149.9 g/mol = 1109.2 g

4. The balanced reaction is this:

3Mg + N₂  →  Mg₃N₂

Ratio is 1:3. Therefore 1 mol of Mg₃N₂ were produced by 3 moles of Mg.

So, 5 moles of Mg₃N₂ would have been produced by 15 moles of Mg. (5 .3)

Let's convert the moles to mass (moles . molar mass)

15 mol . 24.30 g/mol = 364.5 g

5. The reaction is: H₂SO₄ + Mg(OH)₂ →  MgSO₄ + 2H₂O

Ratios are 1:1 and 1:2, between sulfuric acid and the products.

If I have 3 moles of acid, I would produce 3 moles of magnessium sulfate and 6 moles of water (3 .2)

Let's convert the moles to mass

3 mol . 120.36 g/mol = 361.08 g of MgSO₄

6 mol . 18 g/mol = 108 g of H₂O