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irakobra [83]
3 years ago
7

Please anser this asap

Chemistry
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

14 is the 1 st one and the 15 is 3

I am Lyosha [343]3 years ago
4 0
<h2>Answer:</h2><h3>1. both</h3>

An electron in an excited state can release energy and 'fall' to a lower state. When it does, the electron releases a photon of electromagnetic energy. When the electron returns to the ground state, it can no longer release energy but can absorb quanta of energy and move up to excitation states (higher orbitals).

<h3>2. One electron</h3>

An electron will move to the orbital with lowest energy. Each orbital can hold only one electron pair. Electrons will separate as much as possible within a shell.

<em>hope</em><em> </em><em>this</em><em> </em><em>help</em><em>!</em><em> </em><em>Sorry</em><em> </em><em>if</em><em> </em><em>Im</em><em> </em><em>wrong</em><em>. </em>

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Which of the following [H+] values describes the most basic (alkaline) solution?
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The H+ concentration that would best describe a basic solution would be the one having values less than 10^-7. The pH of a solution is related to H+ concentration by pH = -log[H+]. Therefore, as the concentration of H+ decreases the alkalinity would rise. 
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How will the rate at which a solid solute dissolves change if the solution is stirred?
MakcuM [25]

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The rate at which the solute dissolves will increase.

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A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235
trapecia [35]

Answer : The value of \Delta E of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}

Molar mass of helium = 4 g/mole

\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole

Now we have to calculate the heat.

Formula used :

q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

c_p = specific heat of helium = 20.8 J/mol.K

T_1 = initial temperature = 310.0 K

T_2 = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

q=nc_p(T_2-T_1)

q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K

q=-19.5J

Now we have top calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 1.21 L

V_2 = final volume = 0.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (0.99-1.21)L

w=0.22L.artm=0.22\times 101.3J=22.29J

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of \Delta E of the gas.

\Delta E=q+w

\Delta E=(-19.5J)+22.29J

\Delta E=2.79J

Therefore, the value of \Delta E of the gas is 2.79 Joules.

3 0
3 years ago
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