Answer:
oxidation-reduction or redox reaction
Explanation:
n
<span> 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
from the reaction 2 mol 4 mol
from the problem 5.4 mol 10.8 mol
M(CO2) = 12.0 +2*16.0 = 44.0 g/mol
10.8 mol CO2 * 44.0 g CO2/1 mol CO2 = 475.2 g CO2 </span>≈480 = 4.8 * 10² g
Answer is C. 4.8*10² g.
Hey There!:
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
2 moles C2H2 ----------- 5 moles O2
35.0 moles C2H2 ------- moles O2
moles O2 = 35.0 * 5 / 2
moles O2 = 87.5 moles
hope this helps!
Answer is: solution A has 2,57 time greater pH value than solution B.<span>
</span>Concentration of [H⁺] in solution A is than 370x.
pH = -log[H⁺].
pH(solution A) = -log(370x).
pH(solution b) = -log(x).
pH(solution A) / pH(solution B) = -log(370x) / -log(x).
pH(solution A) / pH(solution B) = 2,57.
