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Eddi Din [679]
3 years ago
9

Nitric acid is often manufactured from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming of natural

gas, in a two-step process. In the first step, nitrogen and hydrogen react to form ammonia: (g)(g)(g) In the second step, ammonia and oxygen react to form nitric acid and water: (g)(g)(g)(g) Write the net chemical equation for the production of nitric acid from nitrogen, hydrogen and oxygen. Be sure your equation is balanced.
Chemistry
1 answer:
ikadub [295]3 years ago
5 0

Answer: N_2(g)+3H_2(g)+4O_2(g)\rightarrow 2HNO_3(g)+2H_2O(g)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reaction for nitrogen and hydrogen react to form ammonia:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)     (1)

The balanced chemical reaction for ammonia and oxygen react to form nitric acid and water:

NH_3(g)+2O_2(g)\rightarrow HNO_3(g)+H_2O(g) \times 2

2NH_3(g)+4O_2(g)\rightarrow 2HNO_3(g)+2H_2O(g)    (2)

The net chemical equation for the production of nitric acid from nitrogen, hydrogen and oxygen by adding 1 and 2

N_2(g)+3H_2(g)+4O_2(g)\rightarrow 2HNO_3(g)+2H_2O(g)

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The reaction between NaOH and Cu(NO₃)₂ is as follows

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Q1) stoichiometry of NaOH to Cu(NO₃)₂ is 2:1

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Q2) Assuming that there's 100 % yield of Cu(OH)₂ , we can directly calculate the mass of Cu(OH)₂ formed from the number of moles of reactants that were used up. 

Stoichiometry of Cu(NO₃)₂ to Cu(OH)₂ is 1:1

this means that 1 mole of Cu(NO₃)₂ gives a yield of  1 mole of Cu(OH)₂

the number of Cu(NO₃)₂ moles that reacted - 0.00427 mole 

Therefore an equal amount of moles of Cu(OH)₂ were formed

Then amount of Cu(OH)₂ moles produced - 0.00427 mol

Mass of Cu(OH)₂ formed - 0.00427 mol x 97.56 g/mol = 0.42 g 

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