Answer:
19.6
Step-by-step explanation:
<span>D. 20 + 2âš10 units
To solve this, you simply need to calculate the length of each side of the triangle with the vertexes of A(3,4), B(-5,-2), and C(5,-2). The length of each side is simply calculated using the pythagoras theorem. Note that it doesn't matter what order you do the subtraction. The absolute value will be the same and if it happens to be negative, not a problem since it will become positive once you square the values.
So the length of side AB is
sqrt((3-(-5))^2 + (4-(-2))^2) = sqrt(8^2 + 6^2) = sqrt(64 + 36) = sqrt(100) = 10.
The length of side BC is
sqrt((-5 - 5)^2 + (-2 - (-2))^2) = sqrt(-10^2 + 0^2) = sqrt(100+0) = sqrt(100) = 10.
And finally, the length of side AC is
sqrt((3-5)^2 + (4-(-2))^2) = sqrt(-2^2 + 6^2) = sqrt(4+36) = sqrt(40)
= 2 * sqrt(10)
Finally, add all the lengths together.
10 + 10 + 2âš10 = 20 + 2âš10</span>
Answer c or $31.08 is correct:)
The answer is the first one
Answer:
25x^2 - 60xy + 36y^2
Step-by-step explanation:
(5x - 6y) ( 5x - 6y)
Use foil to get the result when this is expanded.
F: (first term in each factor): 5x*5x = 25x^2
I: Use the last term first factor multiplied by first term second factor
- 6y * 5x = - 30xy
O:Outside. Use first term first factor and last term second factor
5x * -6y = - 30xy
L: last term in both factors -6y * - 6y = 36y^2
All them together
25x^2 - 30xy - 30xy + 36y^2
and combine
25x^2 - 60xy + 36y^2
