Answer:
Step-by-step explanation:
Let X be the initial price in March 2004.
Let X' be the price for March 2005.
Let X" be the price for June 2005.
March 2005: The price was reduced by 20%. Thus, X' = 0.8X
June 2005: The price was reduced by 1/6 of the March 2005 price: Thus,
X" = X' - (1/6)X'
Substituting, we have X" = (0.8X) - (1/6)(0.8X)
X" = (0.8X) - (1/6)(0.8X)
X" = (0.8X) - (0.1333X)
X" = 0.6667X
The June 2005 price is 0.6667 of the 2004 price. That's a (1-0.6667) or 33.33% reduction.
Answer:
<h2>
<em>$</em><em>2</em><em>5</em><em>0</em><em>0</em><em>0</em><em>0</em></h2>
<em>Solution</em>
<em>Selling </em><em>price(</em><em>SP)</em><em>=</em><em>$</em><em>2</em><em>9</em><em>5</em><em>0</em><em>0</em><em>0</em>
<em>profit</em><em> </em><em>percent=</em><em>1</em><em>8</em><em>%</em>
<em>Cost </em><em>price(</em><em>CP)</em><em>=</em><em>?</em>
<em>Now,</em>
<em></em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
Answer:
what
Step-by-step explanation:
wdym by this weirdo
Answer:
Step-by-step explanation:
Given : Sample size : n= 25
Degree of freedom : n-1 = 24
Significance for 95% confidence =
Sample variance :
We assume that the population of all cylindrical engine part outside diameters that would be produced by the new machine is normally distributed
Using chi-square distribution table , Critical values are:
Confidence interval for variance is given by:-
∴ 95% confidence interval for variance :
Answer:
(A) 8y^2 +8y -10
(B) 22y^3 +2y^2 +2y -7
(C) yes, for these polynomials. The result of adding or subtracting the polynomials in this problem is another polynomial, suggesting the set of polynomials is closed to addition and subtraction.
Step-by-step explanation:
A. (4y + 2y^2 − 3) + (−4 + 2y^2 + 2y) + (4y^2 − 3 + 2y)
= y^2(2 +2 +4) +y(4 +2 +2) +(-3 -4 -3)
= 8y^2 +8y -10 . . . . total length of sides 1, 2, 3
__
B. The length of the 4th side is the difference between the perimeter and the sum of the other three sides:
(22y^3 + 10y^2 + 10y − 17) -(8y^2 +8y -10)
= 22y^3 +y^2(10 -8) +y(10 -8) +(-17 +10)
= 22y^3 +2y^2 +2y -7 . . . . length of 4th side
__
C. The result of adding or subtracting the polynomials in this problem is another polynomial, suggesting the set of polynomials is closed to addition and subtraction. An example is not a proof, but there is nothing about this example that would suggest a different conclusion.