The acid dissociation constant is 1.3 × 10^-3.
<h3>What is acid-dissociation constant?</h3>
The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;
Let the acid be HA;
HA + H2O ⇄ H3O^+ + A^-
since the pH of the solution is 2.57 then;
[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3
We can see that; [H3O^+] = [A^-] so;
Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)
Ka = 1.3 × 10^-3
Learn more about acid-dissociation constant: brainly.com/question/9728159
Yes it is c know need anymore help
Answer:
1. First
2. Third
3. Fourth
4.remain the same as
Explanation:
Given the reaction equation;
Rate= k[A] [B]^3
We can see that the order of reaction is first order with respect to reactant A and third order with respect to reactant B. This gives an overall fourth order reaction.
If the concentration of A is doubled and that of B is halved. The rate of reaction remains the same.
I think it might be D or B
And my other two might be A or C
