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Grace [21]
3 years ago
9

Para preparar 1 kilogramo de arcilla se requieren 400 gramos de agua. Si a nivel del laboratorio solo se cuenta con una probeta

y sabemos que la densidad del agua es 1100Kg/m3 ¿Cuántos litros de agua se deben añadir?
Chemistry
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

0.364 L

Explanation:

Para resolver este problema es necesario <em>expresar la densidad en g/L</em>.

Para hacer esa conversión primero <u>convertimos m³ en L</u>:

  • 1 m³ = 1000 L
  • 1100 \frac{kg}{m^3}* \frac{1m^3}{1000L} = 1.1 kg/L

Y después<u> convertimos kg en g</u>:

  • 1.1 kg/L * \frac{1000g}{1kg}= 1100 g/L

Finalmente d<em>ividimos la masa deseada</em> (400 g) <em>entre la densidad</em>, para <u>calcular el volumen</u>:

  • 400 g ÷ 1100 g/L = 0.364 L
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To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

<h3>What is energy of emitted electron?</h3>

The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.

Ee = E - W

<h3>Energy of the emitted electron</h3>

The energy of emitted electrons based on the research of Albert Einstein is given as;

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Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

Learn more about energy of electron here: brainly.com/question/11316046

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8 0
1 year ago
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Concentration - 3

Phase - 1

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