Para preparar 1 kilogramo de arcilla se requieren 400 gramos de agua. Si a nivel del laboratorio solo se cuenta con una probeta
1 answer:
Answer:
0.364 L
Explanation:
Para resolver este problema es necesario <em>expresar la densidad en g/L</em>.
Para hacer esa conversión primero <u>convertimos m³ en L</u>:
- 1 m³ = 1000 L
- 1100
= 1.1 kg/L
Y después<u> convertimos kg en g</u>:
- 1.1 kg/L *
= 1100 g/L
Finalmente d<em>ividimos la masa deseada</em> (400 g) <em>entre la densidad</em>, para <u>calcular el volumen</u>:
- 400 g ÷ 1100 g/L = 0.364 L
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Answer:
Final temperature: 659.8ºC
Expansion work: 3*75=225 kJ
Internal energy change: 275 kJ
Explanation:
First, considering both initial and final states, write the energy balance:
Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:
The pressure is constant, so: (There is a multiplication by 100 due to the conversion of bar to kPa)
So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):
On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:
Subtracting the first from the second:
Isolating :
Assuming that it is water steam, n=0.1666 kmol
ºC