Answer:
Iconic bond or covalent bond
Explanation:
Answer:
232.5 g C2H6O2
Explanation:
The equation you need to use here is ΔTf = i Kf m
Since pure water freezes at 0 C, your ΔTf is just 4.46 C
i = 1 (ethylene glycol is a weak electrolyte)
Kf = molal freezing constant, which for water is 1.86 C/m
m = molality = x mols C2H6O2 / 1.15 kg H2O (don't know the moles of ethylene glycol we're dissolving yet)
Than,
4.46 C = 1.86 C/m (x mol C2H6O2 / 1.15 kg H2O)
Solve for x, you should get x = 2.75 mol C2H6O2
3.75 mol C2H6O2 (62 g C2H6O2 / 1 mol C2H6O2) = 232.5 g C2H6O2
Explanation:The five major branches of chemistry are organic, inorganic, analytical, physical, and biochemistry.
...
Sub-branches of physical chemistry include:
Photochemistry — the study of the chemical changes caused by light.
Surface chemistry — the study of chemical reactions at surfaces of substances
Answer:
0.721 g/L
Explanation:
Ideal gas equation ->PV= nRT ; n= mass (m)/ molar mass (M);
densitiy= mass (m)/ volume (V)
PV= (m/M)*RT -> PVM= mRT -> PM/RT= m/V -> PM/RT=d
We need to put in SI units
105 Kpa= 1.04 atm
25°C= 298 K
d= (1.04 atm * 17 g/ mol)/(0.0821 * 298 K) = 0.721 g/L
E because glucose is a very important energy to help an organism
