Answer: x = 9.6
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Explanation:
We have two smaller right triangles that are glued together so to speak.
The base of the smaller triangle on the left is 5 while the height is h.
Let's use the tangent rule to find the value of h
tan(angle) = opposite/adjacent
tan(55) = h/5
5*tan(55) = h
h = 5*tan(55)
h = 7.14074003371058
Make sure your calculator is in degree mode. That value of h above is approximate.
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Now focus on the smaller triangle on the right
It has the same height value h. This side is the adjacent side while x is the hypotenuse.
We'll use the cosine ratio
cos(angle) = adjacent/hypotenuse
cos(42) = h/x
cos(42) = 7.14074003371058/x
x*cos(42) = 7.14074003371058
x = 7.14074003371058/cos(42)
x = 9.6088135029715
x = 9.6
Answer:
19
Step-by-step explanation:
y=2×8+3
=16+3=19
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For question 7, if we add all votes for tiger and eagle, we get
tiger = 14 + 13 + 8 + 5 = 40
eagle = 6 + 7 + 12 + 15 = 40
so choices A and B are wrong.
C is also wrong because fifth and sixth grade votes for eagle are 6 + 7 = 13 and the 5th and 6th grade votes for tiger are 14 + 13 = 27. clearly 5th + 6th like tiger more.
D is the answer for question 7
question 8
rolling a cube does not affect the other cube so it is all independent probability.
cube: 1 2 3 4 5 6
3 even numbers and 3 odd numbers
so probability of rolling an even number is
1/6 + 1/6 + 1/6 = 3/6 = 1/2
multiplying by total number of rolls, she will get even numberss
300 * 1/2 = 150
about 150 time.
so half of the time, Cassie will roll and even number about half the number of rolls. never exactly since this is all probability. more likely for it to be around 150 times than exactly 150 time.
choice C is answer for question 8
Answer:
20 per hour
Step-by-step explanation:
divide 60 by 3=20
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
