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Helga [31]
3 years ago
10

This formula equation is unbalanced. Pb(NO3)2(aq) + Li2SO4(aq)--> PbSO4(s) + LiNO3(aq). Which coefficient should appear in fr

ont of LiNO3 in the balanced equation?
1
2
3
4
Chemistry
2 answers:
Temka [501]3 years ago
5 0
<span>Balancing is making sure there are the same number of atoms on either side of the reaction.

Pb(NO3)2 + Li2SO4--> PbSO4 + LiNO3

There are 2 NO3 groups and 2 Li on the right side, need 2 on the left side.
Need a coefficient of 2 for LiNO3
</span>
alexgriva [62]3 years ago
4 0

Answer is: coefficient is 2.

Balanced chemical reaction:

Pb(NO₃)₂(aq) + Li₂SO₄(aq) → PbSO₄(s) + 2LiNO₃(aq).

According to principle of mass conservation, number of atoms must be equal on both side of balanced chemical reaction.

There are two lithium atoms, one lead atom, one sulfur atom, ten oxygen atoms and two nitrogen atoms on both side of reaction.

You might be interested in
Using the Hoffman apparatus for electrolysis, a chemist decomposes 2.3 moles of water into its gaseous elements. How many grams
solong [7]

Answer:

2.318032g

Explanation:

-The electrolysis equation of water is written as below:

2H_2O_{(l)}->2H_2_{(g)}+O_2_{(g)}

-The mole ratio of Water to the hydrogen formed is 1:1, therefore 2.3 moles of hydrogen gas is produced.

-Hydrogen's molar mass is 1.00784 grams:

Mass=moles\times molar \ mass\\\\\=2.3\times 1.00784\\\\=2.318032\ g

Hence, 2.318032 grams of hydrogen is produced.

7 0
4 years ago
In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
Please help me with chem, it would be very appreciated!
Lelu [443]

To determine the shapes of molecules, we must become acquainted with the Lewis electron dot structure. Although the Lewis theory does not determine the shapes of molecules, it is the first step in predicting shapes of molecules. The Lewis structure helps us identify the bond pairs and the lone pairs.

Please mark BRAINLIEST.

5 0
3 years ago
What is the solution to the problem expressed to the correct number of significant figures? 2.13 + 1 = ?
Paha777 [63]

So,

With addition, we the last digit we keep will be the one which is known for both individual values.

We know 2.13 to the hundredths, but we only know 1 to the ones.  Therefore, we will round off in the ones place.

2.13 + 1 = 3.13 (unrounded)

= 3 (rounded)

Hope this helps!

7 0
3 years ago
Which of the following statements does not describe a chemical property of oxygen:
g100num [7]
I have a feeling that #2 is the one.
5 0
4 years ago
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