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suter [353]
4 years ago
8

A door has a height of 2.1 m along a y axis that extends vertically upward and a width of 0.975 m along an x axis that extends o

utward from the hinged edge of the door. A hinge 0.47 m from the top and a hinge 0.47 m from the bottom each support half the door's mass, which is 29 kg. In unit-vector notation, what are the forces on the door at (a) the top hinge and (b) the bottom hinge
Physics
1 answer:
Misha Larkins [42]4 years ago
8 0

Answer:

\vec{F_T} = \vec{F_B} = 142.245 N downward

Explanation:

As each hinge supports half the door mass, which is 29kg, then each of them are subjected to 29/2 = 14.5 kg of door mass. Let g = 9.81 m/s2, the weight on each hinge would be:

W = mg = 14.5*9.81 = 142.245 N acting downward

In unit-vector notation, the force vectors on the top and the bottom hinges are:

\vec{F_T} = \vec{F_B} = 142.245 N downward

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