A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42°. What is the force of
2 answers:
Answer:
The correct option is;
75 N
Explanation:
The given parameters are;
The angle of inclination of the ramp, θ = 42°
The gravitational force of the box = m × g = 112.1 N
Let represent the force of static friction acting on the box
Given that the box is at rest, we have
The component of the gravitational force acting along the inclined plane = The force of static friction acting on the box,
We have that the component of the gravitational force acting along the inclined plane = m × g × sin (θ) =
= m × g × sin (θ)
Substituting the values, gives;
= 112.1 × sin (42°) ≈ 75.0095409728
∴ The force of static friction acting on the box = ≈ 75 N
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