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In-s [12.5K]
2 years ago
14

A boy holds a heavy package for one hour. He is very tired but has not done any work. Explain why he did not do any work.

Physics
1 answer:
Feliz [49]2 years ago
5 0

Answer:he's not applying force or motion

Explanation:

p=f & m

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Quantity a of an ideal gas is at absolute temperature t, and a second quantity b of the same gas is at absolute temperature 2t.
olga_2 [115]

Answer: If both gases undergo the same entropy then more heat is added to gas a because the entropy of the gas a is less than the entropy of the gas b.

Explanation:

Entropy is defined as the degree of randomness. When the temperature of the gas increases then the entropy of gas also increases.

In the given problem, Quantity a of an ideal gas is at absolute temperature t, and a second quantity b of the same gas is at absolute temperature 2t.

Heat is added to each gas, and both gases are allowed to expand isothermally. It means that the volume is constant during this process.

If both gases undergo the same entropy then more heat is added to gas a because the entropy of the gas a is less than the entropy of the gas b. If the heat is added then there will be more entropy.

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3 years ago
Poate cineva sa imi rezolve fisa Asta pana Maine?
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Answer:

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5 0
3 years ago
What are 3 facts you learned about the periodic table:
d1i1m1o1n [39]

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7 0
3 years ago
If a cup of coffee has temperature 95∘C95∘C in a room where the temperature is 20∘C,20∘C, then, according to Newton's Law of Coo
lina2011 [118]

Answer:

T = 76.39°C

Explanation:

given,

coffee cup temperature = 95°C

Room temperature= 20°C

expression

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

temperature at t = 0

T( 0 ) = 20 + 75 e^{\dfrac{-0}{50}}

T(0) = 95°C

temperature after half hour of cooling

T( t ) = 20 + 75 e^{\dfrac{-t}{50}}

t = 30 minutes

T( 30 ) = 20 + 75 e^{\dfrac{-30}{50}}

T( 30 ) = 20 + 75 \times 0.5488

T(30) = 61.16° C

average of first half hour will be equal to

T = \dfrac{1}{30-0}\int_0^30(20 + 75 e^{\dfrac{-t}{50}})\ dt

T = \dfrac{1}{30}[(20t - \dfrac{75 e^{\dfrac{-t}{50}}}{\dfrac{1}{50}})]_0^30

T = \dfrac{1}{30}[(20t - 3750e^{\dfrac{-t}{50}}]_0^30

T = \dfrac{1}{30}[(20\times 30 - 3750 e^{\dfrac{-30}{50}} + 3750]

T = \dfrac{1}{30}[600 - 2058.04 + 3750]

T = 76.39°C

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3 years ago
Which of these reactions is responsible for energy radiating from stars, including the Sun?
snow_tiger [21]

Answer: nuclear fusion

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