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arsen [322]
3 years ago
8

How does light reflect off of mirrors and other types of surfaces?

Physics
2 answers:
Feliz [49]3 years ago
8 0

The light reflect off of mirrors and other types of polished surfaces because of reflection.

Explanation:

The polished surfaces can reflect most of the light falling on them.

They will reflect the light waves falling on them as the polished surface or mirrors like objects will be opaque in nature.

The materials which are opaque in nature does not allow light to pass through them or transmit through them.  

When light rays are incident on an object, three kinds of rays will be formed.

They are incident rays which are the source rays hitting the object, the reflected rays which are the rays coming back or get reflected as they are not allowed to penetrate the object and in some cases refracted rays and transmitted rays occur when the rays penetrate partially with different angle or fully with different angle.  

Generally, the opaque objects which have a polished front surface and other surface is closed reflect light waves blocking them to penetrate deeper. So the light will get reflected from the surface.

As the mirrors and most of the bulk surface are opaque in nature, light will not be able to penetrate the depth of those surface and they will get reflected.

Marat540 [252]3 years ago
4 0
Light can reflect from mirrors because mirrors are a prism.
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Answer:

Tect book

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3 years ago
A mass weighing 14 pounds stretches a spring 2 feet. The mass is attached to a dashpot device that offers a damping force numeri
Elodia [21]

Answer:

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

Explanation:

Using the newton second law

k is the spring constante

b positive damping constant

m mass attached

m\frac{d^{2} x}{dt^{2}} = - kx - b\frac{dx}{dt}

x(t) is the displacement from the equilibrium position

\frac{d^{2} x}{dt^{2}} +\frac{b}{m}\frac{dx}{dt} + \frac{k}{m}x = 0

Converting units of weights in units of mass (equation of motion)

m = \frac{W}{g} = \frac{14}{32} = 0.43 slug

From hook's law we can calculate the spring constant k

k = \frac{W}{s} = \frac{14}{2} = 7 lb/ft

If we put m and k into the DE, we get

\frac{d^{2} x}{dt^{2}} +\frac{b}{0.43}\frac{dx}{dt} + 16.28x = 0

Denoting the constants

2λ = \frac{b}{m} = \frac{b}{0.43}

λ = b/0.215

w^{2} = \frac{k}{m} = 16.28

λ^2 - w^2 = \frac{b^{2} }{0.046} - 16.28

This way,

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

3 0
4 years ago
Mechanical energy is a term that is used to describe
larisa86 [58]
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7 0
4 years ago
Can anyone help me with this question please​
JulsSmile [24]

Explanation:

V=u+at

where,

v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

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6=2+2a

2a=6-2

2a=4

a=4/2 = 2

a =2

2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

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5.v=u+at

=5+8*10

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V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

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5 0
3 years ago
How are weather from ice and plants different from weathering from wind and water?
DENIUS [597]
“Weathering is the breaking down of rocks, soil and minerals as well as wood and artificial materials through contact with the Earth’s atmosphere, biota and waters. Weathering occurs in situ, roughly translated to: “with no movement”, and thus should not be confused with erosion, which involves the movement of rocks and minerals by agents such as water, ice, snow, wind, waves and gravity and then being transported and deposited in other locations.”

Weathering processes are of three main types: mechanical, organic and chemical weathering.
7 0
3 years ago
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